Answer:
Area of Triangle QRP = 3
Step-by-step explanation:
According to Question , We have a circle With Centre 'O' & Area 48
.
Area Of Circle = 48

= 48
r = 
Now We Have Two Points Given On Circle Q & R , P Is Circumcentre Of Triangle QRO .
Thus A Circle Can Also Be Formed with Centre P . ( See attachment For Diagram )
Now The Diameter of Circle With Centre P = Radius Of Circle with Centre O
so Radius Of Circle With Centre P(
) = 
Now We Have To Find Area Of Equilateral Triangle .
A =
A= 
The Area Of PQR is = 3
For Diagram , Please Find In Attachment
Answer:
Congrats!
Step-by-step explanation:
Answer and Step-by-step explanation:
These two terms (pronounced as Sine and Cosine) are used to solve for the sides and angles of a triangle in Trigonometry.
They are functions revealing the shape of a right triangle.
Sine is a trigonometric function of an angle. The sine of an acute angle is defined in the context of a right triangle: for the specified angle, it is the ratio of the length of the side that is opposite that angle, to the length of the longest side of the triangle.
Cosine is also a trigonometric function of an angle. The cosine of an angle is the relation of the length of the side that is adjacent that angle, to the length of the longest side of the triangle.
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
Answer:
60 dimes 35 nickels
Step-by-step explanation:
<span>2/5 is close to 1/2, and it is easy to find 1/2 of 7 mentally. Half of 7 is 3.5, so Martin gave away about 3.5 pounds.</span>