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qwelly [4]
3 years ago
13

Hera spent $16 on dinner then she spent $6 on dessert and some more on a taxi ride including the taxi fair she spent a total of

$31 how much money did Hera spend on the taxi ride
Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
8 0

She spent $9.

$16+$6 is $22, so the total $31 minus $22 leaves us with the $9 she spent for the taxi.

earnstyle [38]3 years ago
8 0

$9

You find 16+6 (22)

That is the total cost for everything except the taxi. To find it out, you would find the difference between 31 and 22.

You find this by:

31-22=9

9


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Also, we have 8 inches of cord for each bracelet and 20 inches of cord for each necklace, then the total length for the bracelet is 8x and that for the necklace is 20y.

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2x + 5y = 30  (3).

Writing equations (1) and (3) in matrix form, we have

\left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}9\\30\end{array}\right]

Using Cramer's rule to solve for x and y,

x = det \left[\begin{array}{ccc}9&1\\30&5\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\

x = (9 × 5 - 30 × 1) ÷ (1 × 5 - 1 × 2)

x = (45 - 30) ÷ (5 - 2)

x = 15 ÷ 3

x = 5

y = det \left[\begin{array}{ccc}1&9\\2&30\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\

y = (30 × 1 - 9 × 2) ÷ (1 × 5 - 1 × 2)

y = (30 - 18) ÷ (5 - 2)

y = 12 ÷ 3

y = 4

So Philip made 5 bracelets and 4 necklaces.

3 0
3 years ago
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