Answer:
you needed to mark this question for the science section
Step-by-step explanation:
Answer:
<I= 15degrees
Step-by-step explanation:
Using the cosine rule formulae;
j² = i²+k²-2i cos <J
j² = 37²+57² - 2(37)(57)cos <141
j² = 1369+ 3249- 4218cos <141
j² = 4618- 4218cos <141
j² = 4618-(-3,278)
j²= 7,896
j = √7,896
j = 88.86inches
Next is to get <I
i² = j²+k²-2jk cos <I
37² = 88.86²+57² - 2(88.86)(57)cos <I
1369 = 7,896.0996+ 3249- 10,130.04cos <I
1369 = 11,145.0996 - 10,130.04cos <I
1369 - 11,145.0996 = - 10,130.04cos <I
-9,776.0996=- 10,130.04cos <I
cos <I =9,776.0996 /10,130.04
cos<I = 0.96506
<I = 15.19
<I= 15degrees
Answer:
3
Step-by-step explanation:
2x^9 = 1
3x^6 = 2
- x - 20 = 3
This problem can be represented through the following equation
A = A₀(1/2)^t/h
where
A-----------> is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h-------------> is the half-life-----------> 8 days
for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days
the answer is 45.15 days
Answer:
The answer is 32x+67
Step-by-step explanation:
