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We have that
2r−9≤−6------> 2r ≤ -6+9-------> 2r ≤ 3-----> r ≤ 1.5
the solution is the interval (-∞, 1.5]
using a graph tool
see the attached figure
2r−9≤−6------> 2r ≤ -6+9-------> 2r ≤ 3-----> r ≤ 1.5
the solution is the interval (-∞, 1.5]
using a graph tool
see the attached figure