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Dvinal [7]
3 years ago
8

Please help! Due very soon!

Mathematics
1 answer:
Arada [10]3 years ago
8 0

Answer:

9

6

3

3

6

3

3

multiply

row

18

32

Step-by-step explanation:

The answer to each blank, in order from top to bottom

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Answer:

6

Step-by-step explanation:

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Solve equations: 3|x+4|=6<br><br> | = absolute value
Anestetic [448]

Absolute values are a way of finding a distant from zero, which means there will be 2 answers; one will be positive, and the other will be negative.

|<em>3x - 4</em>| = 5<em>and</em> |3<em>x - 4</em> = a^5 Because you need 2 answers, you have to make 5 positive and negative.

Another way to write this equation would be...

5=|3x-4|=—5

Now lets continue...

5=3x-4=—5

Add 4 to both sides...

9=3x=—1

Now divide by 3...

3=x= -1/3

So the solution is...

X={-1/3  3}

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Today Cenisa runs 450 meters more than yesterday. Yesterday she ran 1.23 kilometers. How many meters does Cenisa run today?
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Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

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3 years ago
Faces of a rectangular prism and a cude
Vladimir79 [104]
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