Answer: 4 times
Solution: 60 minutes * 7 = 420
280/420 = ans
ans * 6 = 4
In ijk notation, the boat has velocity (relative to the water)
![\vec v_{B/W}=(22\,\vec\imath)\dfrac{\rm km}{\rm hr}](https://tex.z-dn.net/?f=%5Cvec%20v_%7BB%2FW%7D%3D%2822%5C%2C%5Cvec%5Cimath%29%5Cdfrac%7B%5Crm%20km%7D%7B%5Crm%20hr%7D)
and the current has velocity (relative to the Earth)
![\vec v_{W/E}=(10\cos225^\circ\,\vec\imath+10\sin225^\circ\,\vec\jmath)\dfrac{\rm km}{\rm hr}](https://tex.z-dn.net/?f=%5Cvec%20v_%7BW%2FE%7D%3D%2810%5Ccos225%5E%5Ccirc%5C%2C%5Cvec%5Cimath%2B10%5Csin225%5E%5Ccirc%5C%2C%5Cvec%5Cjmath%29%5Cdfrac%7B%5Crm%20km%7D%7B%5Crm%20hr%7D)
The boat's "true" velocity (relative to the Earth) satisfies
![\vec v_{B/E}=\vec v_{B/W}+\vec v_{W/E}](https://tex.z-dn.net/?f=%5Cvec%20v_%7BB%2FE%7D%3D%5Cvec%20v_%7BB%2FW%7D%2B%5Cvec%20v_%7BW%2FE%7D)
so that
![\boxed{\vec v_{B/E}=(14.93\,\vec\imath-7.07\,\vec\jmath)\dfrac{\rm km}{\rm hr}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cvec%20v_%7BB%2FE%7D%3D%2814.93%5C%2C%5Cvec%5Cimath-7.07%5C%2C%5Cvec%5Cjmath%29%5Cdfrac%7B%5Crm%20km%7D%7B%5Crm%20hr%7D%7D)
which translates to a speed of about 16.5 km/hr in a direction of 25.48º South of East.
Answer:
16
Step-by-step explanation:
Use the equation
, where a is one leg, b is the other, and c is the hypotenuse.
Answer:
<h2><em><u>No Solutions</u></em></h2>
Explanation:
2(x + 1) = 2x + 1
- Simplify both sides of the equation
2(x + 1) = 2x + 1
(2)(x) + (2)(1) = 2x + 1 [Distribute]
- Subtract 2x from both sides
2x + 2 − 2x = 2x + 1 − 2x
2 = 1
- Subtract 2 from both sides
2 − 2 = 1 − 2
0 = −1
<h2><u><em>This Is False, Therefore There Are No Solutions</em></u></h2>
- PNW
Answer:
Step-by-step explanation:
Since point B is located between A and C
then
AB + BC = AC
or, 3x-16 + 4x-8 = 60
or, 7x = 60 + 24
or, 7x = 84
x = 12