The logarithmic model for the length when the strength is of 8 Pascals is given by:
![f^{-1}(8) = \log_{2}{8} = \log_2{2^3} = 3](https://tex.z-dn.net/?f=f%5E%7B-1%7D%288%29%20%3D%20%5Clog_%7B2%7D%7B8%7D%20%3D%20%5Clog_2%7B2%5E3%7D%20%3D%203)
- That is, the length is of 3 units.
<h3>What is the function?</h3>
The strength in Pascals for a building of length x is given by:
![f(x) = 2^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%202%5Ex)
To find the length given the strength, we apply the inverse function, that is:
![2^y = x](https://tex.z-dn.net/?f=2%5Ey%20%3D%20x)
![\log_{2}{2^y} = \log_2{x}](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%7B2%5Ey%7D%20%3D%20%5Clog_2%7Bx%7D)
![y = \log_2{x}](https://tex.z-dn.net/?f=y%20%3D%20%5Clog_2%7Bx%7D)
Hence, when the strength is of 8 Pascals,
, and the length is given by:
You can learn more about logarithmic functions at brainly.com/question/25537936
Answer:
$204
Step-by-step explanation:
The question is at what price x will the company maximize revenue.
The revenue function is:
![R(x) = 4,080x-10x^2](https://tex.z-dn.net/?f=R%28x%29%20%3D%204%2C080x-10x%5E2)
The price for which the derivate of the revenue function is zero is the price the maximizes revenue:
![R(x) = 4,080x-10x^2\\\frac{dR(x)}{dx}=0=4,080-20x\\x=\frac{4,080}{20}\\ x=\$204](https://tex.z-dn.net/?f=R%28x%29%20%3D%204%2C080x-10x%5E2%5C%5C%5Cfrac%7BdR%28x%29%7D%7Bdx%7D%3D0%3D4%2C080-20x%5C%5Cx%3D%5Cfrac%7B4%2C080%7D%7B20%7D%5C%5C%20x%3D%5C%24204)
The company will maximize its revenue when the price is $204.
Answer:The taxi ride that is m miles long would cost as follows: 4 + m
Step-by-step explanation:
Cubic stack would mean all the sides are the same length.
The length of the side is given as 3 yards.
Volume = 3^3 = 3 x 3 x 3 = 27
Volume = 27 cubic yards.