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BigorU [14]
3 years ago
5

State a definition for a polygon inscribed in a sphere.

Mathematics
1 answer:
mojhsa [17]3 years ago
4 0

Consider the situation given below:

Let a regular polygon be inscribed in a sphere such that its circumcentre is at a distance r from the centre of the sphere of radius R. A point source of light is kept at the centre of the sphere. How can we calculate the area of the shadow made on the surface of the sphere.

I tried to use the relation: <span>Ω=<span>S<span>R2</span></span></span>

But of course that is the case when a circle would be inscribed. So can I somehow relate it for any general polygon?


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Hey can you please help me posted picture of question
Galina-37 [17]
Since the events are dependent, the probability of occurrence of event B will impact the probability of occurrence of event A. So we will be using the formula of conditional probability to find P(A ∩ B).

P(A|B)= \frac{P(A*B)}{P(B)} \\  \\ &#10;P(A*B)=P(A|B)P(B)

Here P(A*B) indicates P(A ∩ B).

Using the values, we get:

P(A ∩ B) = 0.25 x 0.4 = 0.1

Thus, option A gives the correct answer.
5 0
3 years ago
Please need help with 4 and 5
ArbitrLikvidat [17]
1) 3. 5*10^8
2) A
8. 64*10^4

6 0
3 years ago
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Assoli18 [71]
The answer to the questions

4 0
4 years ago
In the figure to the right, AB=7 1/2m, BC=2 1/4 m, and DE=1 1/4m. Find the perimeter of the figure if all angles are right.
Eduardwww [97]

Answer:

22 meters

Step-by-step explanation:

What we know:

Side AB is 7 1/2 m long, Side BC is 2 1/4 m long, and Side DE is 1 1/4 m long.

Saying Sides AH and FG are the same as Sides DE and BC respectively, we can add another 3 1/2 m to the perimeter.

If CD, EF and GH are each 1/3 of AB, then 7 1/2 is added again.

7.5 + (2.5 * 3) * (2.25 * 2) + (1.25 * 2)

7.5 + 7.5 + 4.5 + 2.5

15 + 7

The perimeter is 22 meters.

5 0
3 years ago
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Pls help (if this is the right picture)
Elden [556K]
The answer is the last one bc 2.55 divided by 8 is 0.21
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3 years ago
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