1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vedmedyk [2.9K]
2 years ago
7

How do I solve for the variables r,s, and t

Mathematics
1 answer:
Softa [21]2 years ago
4 0
When using variables, and the whole question is full of variables. The letters can stand for anything.
You might be interested in
In the Journal of Shell and Spatial Structures (December 1963), environmental researcher Vivek Ajmani studied the performance of
igomit [66]

Answer:

The standard deviation of the load distribution is of 5102.041 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 20000

Also, the probability that the load is between 10,000 and 30,000 pounds is 0.95.

10,000 pounds and 30,000 pounds are equidistant from the mean. Due to this, and the probability of 0.95 of having a value in this range, 10000 is the (100-95)/2 = 2.5th percentile and 30000 is the (100+95)/2 = 97.5th percentile. Applying one of them, we find the standard deviation.

30,000 is the 97.5th percentile:

This means that when X = 30000, Z has a pvalue of 0.975. So when X = 30000, Z = 1.96. Then

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{30000 - 20000}{\sigma}

1.96\sigma = 10000

\sigma = \frac{10000}{1.96}

\sigma = 5102.041

The standard deviation of the load distribution is of 5102.041 pounds.

8 0
3 years ago
Please help me not hard please
IrinaVladis [17]

Answer:

I think it's A

Step-by-step explanation:

8 0
3 years ago
3a+4b=5a-t solve for a
7nadin3 [17]

Answer:

2b+t/2=a

Step-by-step explanation:

3a + 4b = 5a-t

-3a           -3a

4b = 2a - t

+t         +t

4b + t = 2a

/2           /2

2b+t/2=a

5 0
2 years ago
Read 2 more answers
it took Bob 55 minutes to clean the garbage. How many seconds did it take bob?there are 60 seconds in one minute please help me
defon

Answer:

3,300 sec

Step-by-step explanation:

7 0
3 years ago
Simplify each expression. 6mn3 -mn2 + 3mn3 +15mn2??
bekas [8.4K]

Answer:

9m(n)^3 +14m(n)^2

Step-by-step explanation:

6m(n)^3 - m(n)^2 + 3m(n)^3 + 15m(n)^2

=> 6m(n)^3 + 3m(n)^3 + 15m(n)^2 - m(n)^2

=> 9m(n)^3 +14m(n)^2

4 0
3 years ago
Other questions:
  • Write each fraction or mixed number as a decimal -1 2/9
    13·1 answer
  • True or false the base of a triangular pyramid is a triangle​
    10·2 answers
  • NEED HELP ASAP!!! Will give brainlest
    12·2 answers
  • An auto travels at a rate of 25 km/hr for 4 minutes, then at 50 km/hr for 8 minutes, and finally at 20 km/hr for 2 minutes. find
    12·1 answer
  • In the class , 0.48 of the students have brown hair. 3/11 of the students have blonde hair . What percent of students have neith
    15·1 answer
  • a carpenter uses four nails to install each shelf. complete the table to represent the relationship between the number of nails
    5·1 answer
  • The area of a circle is 25 pi square units what is the radius
    15·1 answer
  • Four more than five times a number is less than 54. evaluate this problem situation for values of the number.
    10·2 answers
  • Pleas help ASAP please please . Thank you so much
    7·2 answers
  • Identify the construction at the figure represents
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!