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kobusy [5.1K]
3 years ago
7

Help me with this please. x = ? use socatoah

Mathematics
2 answers:
Sphinxa [80]3 years ago
8 0

Answer:

this answer is not right because the Y is not 90 degrees the Z angle is 90 degrees so the answer should be 26

if the trangle is right trangle use Phythagoras

576-100=476=x²

x²=476

x=2√119

klemol [59]3 years ago
4 0

Answer:

26

Step-by-step explanation:

In\: \odot Y, WZ is tangent to the circle at point Z and YZ is radius.

\therefore YZ \perp WZ

(tangent radius theorem)

\therefore m\angle WZY = 90\degree

Since, side opposite to 90° angle is called hypotenuse.

So, x represents the length of hypotenuse of \triangle WYZ

Thus, by Pythagoras Theorem

x =  \sqrt{ {24}^{2}  +  {10}^{2} }  \\  \\  =  \sqrt{576 + 100}  \\  \\  =  \sqrt{676}  \\  \\  = 26

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Underoot 60 = 
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3 years ago
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Please I need help ASAP<br>pls explain your answer ​
USPshnik [31]

Answer:

47.62 cm

Step-by-step explanation:

ABCD is a rhombus. Each side measures 15 cm.

m<A = 60°.

Here are some properties of a rhombus:

Opposite angles of a rhombus are congruent.

m<C = m<A = 60°

m<ADC = m<ABC

The sum of the measures of the interior angles of a quadrilateral is 360°.

The diagonals are perpendicular bisectors of each other.

m<A + m<C + m<ADC + m<ABC = 360°

60° + 60° + 2m<ADC = 360°

2m<ADC = 240°

m<ADC = 120°

Each diagonal of a rhombus bisects a pair of congruent, opposite angles.

m<ADB + m<CDB = m<ADC

m<ADB = m<CDB

m<ADB + m<ADB = 120°

m<ADB = 60°

Triangle ABD had two angles, <A and <ADB, that measure 60°. Therefore, the third angle, <ABD also measures 60°. That makes triangle ABD an equilateral triangle.

Draw segment AT.

T is the midpoint of BD. The segment AT is the perpendicular bisector of segment BD. Triangle ATD is a 30-60-90 triangle.

Using the ratio of the lengths of the sides of a 30-60-90 triangle, we can calculate the length of AT which is the radius of circle A.

TD : AT : AD

1    : √3 :   2

AD = 15 cm

TD = AD/2

AT = √3 × TD

AT = (AD√3)/2

AT = 7.5√3 = 12.99

AQ = 12.99

perimeter = QD + PB + m(arc)PTQ + BC + CD

perimeter = (15 - 12.99) + (15 - 12.99) + 60°/360° × 2π(12.99) + 15 + 15

perimeter = 47.62

Answer: perimeter = 47.62 cm

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y = x \times 0.025
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Answer:

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Step-by-step explanation:

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6 0
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Answer:

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