Answer:
25 m/s
Explanation:
This question can be solved using equation of motion
where
v is the final velocity
u is the initial velocity
s is the distance covered while moving from initial to final velocity
a is the acceleration
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Given
box moved for distance of 62.5 m
Friction slows the box at –5.0 m/s2----> this statement means that there is deceleration , speed of truck decreases by 5 m/s in every second until the box comes to rest. Friction causes this deceleration.
thus in this problem
a = -5.0 m/s2
V = 0 as body came to rest due to friction deceleration
u the initial velocity we have to find
the initial velocity of box will be the same as speed of truck, as the box was in the truck and hence box will pick the speed of truck.
so if we find speed of box, we will be able get sped of truck as well.
using equation of motion
Thus, initial speed with the truck was travelling was 25 m/s.
Explanation:
The pressure on the master piston = the pressure on the slave piston
P₁ = P₂
Pressure is force divided by area:
F₁ / A₁ = F₂ / A₂
Here, F₁ = 20 N, A₁ = 10 cm², and F₂ = 60 N.
(20 N) / (10 cm²) = (60 N) / A₂
A₂ = 30 cm²
The core difference is that heat deals with thermal energy, whereas temperature is more concerned with molecular kinetic energy. Heat is the transfer of thermal energy, whereas temperature is a property the object exhibits.
Answer:
The friction of the string and its pivotal anchor point cannot be eliminated. The precise measurement of the length of the pendulum is difficult to take by using meter sticks or rulers. The value of the acceleration due to gravity g in the locality is not constant and must be obtained from reliable sources.
Answer:
5.03 m/s
Explanation:
Give
Speed = v = 24m/s
Wavelength = λ = 30cm = 0.3m
Amplitude = A = 1.0cm = 0.01m
The velocity of a point in Simple Harmonic Motion
at any time t is given by the following formula
v = ωA cos ωt
The value is the Maximum when cosωt.
The maximum value of cosωt. is 1.
Hence the maximum velocity is ωA
Velocity of the wave v=n λ
n = v/ λ = 24 /0.3 = 80
ω = 2πn = 2π*80 = 502.86 rad/s
Maximum velocity of the particle is
ωA = 502.86 * 0.01 = 5.03m/s