Answer:
lamda=10.5m
Explanation:
using the equation of progressive wave.
y=Asin(wt-kx)
comparing the two equations together, we have
kx=0.6x , k=0.6
k=2π/λ
0.6=2*3.142/λ
cross multiply
0.6λ=6.284
divide both sides by 0.6
λ=6.284/0.6
λ=10.47m
approximate
λ=10.5m
Answer:
A. it contains ultraviolet, visible, and infrared light
Answer:
Explanation:
Given that,
Initially, the spaceship was at rest, u = 0
Final velocity of the spaceship, v = 11 m/s
Distance accelerated by the spaceship, d = 213 m
We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.
So, the acceleration experienced by the occupants of the spaceship is 
.
Answer:
A)0.00022s b)40363.6N c) 0.025m/s
Explanation:
Mass = 24g = 0.024kg, distance though the target = thickness of the target = 25cm = 0.25m
Initial speed of the bullet = 1300m/s, final speed = 930m/s
Using equation of motion
Distance = 1/2(vf+vi)*t (time in seconds)
t = 0.25*2/(1300+930) = 0.00022s
B) force exerted on the body
F = ma = m* (vf-vi)/t = 0.024*(930-1300)/0.00022
F = -40363N, it is negative because the body decelerated during this motion
C) using law of conservation of momentum,
M1*U1+ M2*U2(M2and U1 are the mass and initial speed of the body) = M1V1+ M2V2
The target was at rest so initial speed U2 = 0
0.024*1300 + 360*0 = 0.024*930 + 360*V2
31.2 = 22.32+360*V2
31.2-22.33 = 360*V2
V2 = 8.88/360 = 0.025m/s
Answer: The client must be advised while preparing a goal either for a treatment or for a fitness class.
Explanation:
The client goal must be set in a way that it should be measurable, attainable, time-bound.
The measurable goal is the in the sense that the client can measure own success.
The attainable is in the sense the client can achieve and perform all set plans in the goal.
Time-bound is in the sense that the client can devote sufficient time to obtain success.
