Question

What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons?

Answer 1

Answer:

181.82N

Explanation:

We have the following:

Coefficient of kinetic friction: $\mu=0.22$

Kinetic frictional force: $f=40N$

and we have a formula that relates these two quantities:

$f=\mu N$

where $N$ is the normal force. So since the normal force is what we are asked for, we clear for N in the last equation:

$N=\frac{f}{\mu}$

and substituting all the known values:

$N=\frac{40N}{0.22} =181.818N$

The normal force has a value of 181.82N

Answer 2

Hope this helps you!