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3 years ago

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What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newt

ons?

2 answers:

horrorfan [7]3 years ago

8 0

Answer:

181.82N

Explanation:

We have the following:

Coefficient of kinetic friction: $\mu=0.22$

Kinetic frictional force: $f=40N$

and we have a formula that relates these two quantities:

$f=\mu N$

where $N$ is the normal force. So since the normal force is what we are asked for, we clear for N in the last equation:

$N=\frac{f}{\mu}$

and substituting all the known values:

$N=\frac{40N}{0.22} =181.818N$

The normal force has a value of 181.82N

ipn [44]3 years ago

5 0

Hope this helps you!

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A spherically-spreading EM wave comes from a 104.0 W source. At a distance of 9.6 m, what is the intensity of the wave?

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Answer:

Approximately 0.0898 W/m².

Explanation:

The intensity of light measures the power that the light delivers per unit area.

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The surface area of a sphere of radius $r$ is equal to $4\pi r^{2}$ . For the imaginary 9.6-meter sphere here, the surface area will be:

$\rm 4\pi \times (9.6\; m)^{2} \approx 1158.12\; m^{2}$ .

That $\rm 104.0\; W$ power is spread out evenly over this 9.6-meter sphere. The power delivered per unit area will be:

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3 years ago

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<u>Explanation:</u>

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3 years ago

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Answer:

Explanation:

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You can get these other numbers similarly:

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3 years ago