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slava [35]
3 years ago
8

What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newt

ons?

Physics
2 answers:
horrorfan [7]3 years ago
8 0

Answer:

181.82N

Explanation:

We have the following:

Coefficient of kinetic friction: \mu=0.22

Kinetic frictional force: f=40N

and we have a formula that relates these two quantities:

f=\mu N

where N is the normal force. So since the normal force is what we are asked for, we clear for N in the last equation:

N=\frac{f}{\mu}

and substituting all the known values:

N=\frac{40N}{0.22} =181.818N

The normal force has a value of 181.82N

ipn [44]3 years ago
5 0
Hope this helps you!

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