The answer is 260 for the LCM
For the seagull to catch the crab, h(t)=g(t) so:
-16t^2+45=-13t+23 add 16t^2 to both sides
45=16t^2-13t+23 subtract 45 from both sides
16t^2-13t-22=0 using the quadratic equation:
t=(13±√1577)/32, since t>0
t=(13+√1577)/32 seconds
t≈1.65 seconds (to nearest hundredth of a second)
And the height that this occurs using either original equation is:
h((13+√1577)/32)≈1.59 ft (to nearest hundredth of a foot)
If you need the answer so go to the google and search for problem
Answer:
<em>m=-1/2</em>
Step-by-step explanation:
The equation is in y=mx+b form. M is the slope. In this equation, -1/2 is m.
Therefore the slope is -1/2.
