<span>x + (x + 1)
.............
</span>
Answer:
Step-by-step explanation:
Let's solve 2x^2 = -X^2 - 5x - 1. Consolidate all terms on the left side and write 0 on the right side:
3x^2 + 5x + 1 = 0. This is a quadratic equation. Let's solve it for x using the quadratic formula:
a = 3, b = 5, c = 1, and so the discriminant is b^2 - 4ac = 5^2 - 4(3)(1) = 13. Because the discriminant is positive, we know that there are two distinct, real roots; the graphs of y = 2x^2 and y = x^2 - 5x - 1 intersect in two places whose x-coordinates are the real roots mentioned above.
Answer A is not correct as stated, but would be correct if we were to replace "the y-coordinates" with "the x-coordinates."
Answer C would be correct if and only if we write y = x^2 - 5x - 1.
Answer:
A is your answer, my guy
Step-by-step explanation:
4x1=4
3x-1=-3
5x1=5
4+(-3)+5=6
6x1=6
8x-1=-8
6x1=6
6+(-8)+6=4
4x1=4
2x-1=-2
6x1=6
4+(-2)+6=8
The answer to that question is 62x ()//‘’::;;
