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Lesechka [4]
2 years ago
7

The inequality x + 2y ≥ 3 is satisfied by point (1, 1). True False

Mathematics
2 answers:
andre [41]2 years ago
7 0
In the given statement above, in this case, the answer would be TRUE. It is true that the  inequality x + 2y ≥ 3 is satisfied by point (1, 1). In order to prove this, we just have to plug in the values. 1 + 2(1) <span> ≥ 3 
So the result is 1 + 2 </span> ≥ 3. 3 <span> ≥ 3, which makes it true, because it states that it is "more than or equal to", therefore, our answer is true. Hope this answer helps.</span>
ki77a [65]2 years ago
6 0

Answer:

True

Step-by-step explanation:

We can check by substitute x=1 into the inequality to determine if the y will be equal to 1 or more:

1+2y≥3

solve for y:

2y≥3-1

y≥2/2

y≥1

y is equal to 1 or more. Therefore the inequality is satisfied for point (1,1)

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Peter made two transactions today at his bank. what can the sum -47.27 plus 598= 550.73 mean in terms of peters bank account? i
Alja [10]

Answer:

Peter withdrew $47.27 and deposited $598, decreasing his balance by $550.73.

Step-by-step explanation:

He took $42.27 from his bank account, and then put in $598, which made the final total $550.73

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3 years ago
Thuy rolls a number cube 7 times. which expression represents the probability of rolling a 4 exactly 2 times?
Nady [450]
The result of rolling a number cube 7 times is a 7-digit number composed of digits 1,2,3,4,5 and 6 so that digits can repeat. The total number of possibilities is 6^7.

The number of possibilities where 4 appears exactly two times is 5^5*(7!-6!/2).
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6 0
3 years ago
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ddd [48]

Answer:

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3 years ago
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Section 5.2 Problem 17:
Elina [12.6K]

This DE has characteristic equation

4r^2 - 12r + 9r = (2r - 3)^2 = 0

with a repeated root at r = 3/2. Then the characteristic solution is

y_c = C_1 e^{\frac32 x} + C_2 x e^{\frac32 x}

which has derivative

{y_c}' = \dfrac{3C_1}2 e^{\frac32 x} + \dfrac{3C_2}2 x e^{\frac32x} + C_2 e^{\frac32 x}

Use the given initial conditions to solve for the constants:

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and so the particular solution to the IVP is

\boxed{y(x) = 3 e^{\frac32 x} - 2 x e^{\frac32 x}}

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2 years ago
I need to know how to solve ASAP!! Thanks!
Viktor [21]

Answer:

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Step-by-step explanation:

Brainly

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