We're given the algebraic expression 2x^2 - 2z^4 + y^2 - x^2 + z^4
By hypothesis, x = -4, y = 3 and z = 2
Let's replace each letter by its given value:
2x^2 - 2z^4 + y^2 - x^2 + z^4
2(-4)^2 - 2(2)^4 + (3)^2 - (-4)^2 + (2)^4
(2*16) - 2*16 + 9 - 16 + 16
32 - 32 + 9 - 16 + 16
9
So wrong. The correct answer is not -3, but 9.
Hope this helps! :D
Answer:
120 cubes
Step-by-step explanation:
Find the volume of the prism and then divide it by the volume of one cube (which is 1/27 cm):
V = length*width*height = (5/3 cm)(4/3 cm)(2 cm) = 40/9 cm³.
Dividing this result by 1/27 yields
40 27 40*3
------ * ------ = -------------- = 120
9 1 1
120 cubes (answer)
The answer is there with the attached peice
Answer:
f(3) = 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 1/3x + 5
f(3) is x = 3
<u>Step 2: Evaluate</u>
- Substitute: f(3) = 1/3(3) + 5
- Multiply: f(3) = 1 + 5
- Add: f(3) = 6
Perfect squares are n² where n is a whole number
whole numbers are like 0,1,2,3,4,5,6, etc
no decimal or fractions
we can do that be looking at the perfect squares we know
2²=4
3²=9
4²=16
5²=25
6²=36
7²=49
8²=64
etc
so we see 47 is between 6² and 7²
therefor, for n²=47, n is between 6 and 7 and is therfore not a whole number
that makes 47 not a perfect square