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9966 [12]
2 years ago
6

If a radius of a circle is 12 feet, what is the area and perimeter of the circle?

Mathematics
2 answers:
Marysya12 [62]2 years ago
6 0

Answer:

Area: 452.4

Perimeter: 75.4 ft

Step-by-step explanation:

Formula for area: \pi r^{2}

Formula for perimeter: \pi d or 2\pi r

Vesna [10]2 years ago
4 0
Area of a circle=πr²
area of this cirlce=π*(12 ft)²=144π ft²≈452.39 ft².

answer 1= the area of this circle is 452.39 ft².

Perimeter of a circle=2πr.
Perimeter of this cirlce=2π(12 ft)=24π ft≈75.4 ft

<span>answer 2= the perimeter of this cirlce is 75.4 ft.</span>

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A cylinder has a volume of 45 pi and radius of 3 what is the height? Plzz help it’s due tomorrow
VARVARA [1.3K]

Answer:

Height = 5

Step-by-step explanation:

Solution,\\Volume(V)=45\pi \\Radius(r)=3\\Height(h)=?\\As,\\V=\pi r^{2} h\\45\pi =\pi (3)^{2} h\\\frac{45\pi }{9\pi } =h\\h=5

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3 years ago
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Angle RST is a right angle. Angle RSU has a measure of 25°.
Angelina_Jolie [31]

Keywords

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we know that

If two angles are <u>complementary angles</u>, then their sum is equal to a <u>right angle</u>

In this problem

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3 years ago
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a boy is standing on a pole of height 14.7m throws a stone upwards. it moves in a vertical line slightly away from the pole and
fomenos

Answer:

The time taken for the upward motion is 1 second. The same time is taken for the downward motion

It reaches a maximum height of 4.9 meters.

Step-by-step explanation:

The equation of motion is:

x(t) = -4.9t^{2} + 9.8t

Since the term which multiplies t squared is negative, the graph is concave down, that is, x increases until the vertex, where it reaches it's maximum height, then it decreases.

Vertex of a quadratic equation:

Quadratic equation in the format x(t) = at^{2} + bt + c

The vertex is the point (t_{v}, x(t_{v})), in which

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In this question:

x(t) = -4.9t^{2} + 9.8t

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Vertex:

t_{v} = -\frac{9.8}{2*(-4.9)} = 1

The time taken for the upward motion is 1 second.

x(t_{v}) = x(1) = 9.8*1 - 4.9*(1)^{2} = 4.9

It reaches a maximum height of 4.9 meters.

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From the vertex to the ground.

The ground is t when x = 0. So

-4.9t^{2} + 9.8t = 0

4.9t^{2} - 9.8t = 0

4.9t(t - 2) = 0

4.9t = 0

t = 0

Or

t - 2 = 0

t = 2

It reaches the ground when t = 2 seconds.

The downward motion started at the vertex, when t = 1.

So the duration of the downward motion is 2 - 1 = 1 second.

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