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Nastasia [14]
3 years ago
5

(15 POINTS) Solve (Equation in picture)

Mathematics
1 answer:
yulyashka [42]3 years ago
5 0
Your answer is B. -4 +/- 2 6 do you need an explanation?
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If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.a. trueb. false
grin007 [14]
This is true.only parallelograms have diagonals that both bisect each other.
5 0
4 years ago
Abby and Cruz are playing a game .abby’s score is 586 points Cruz’s score is 754 Abby estimates she needs about 200 points more
bonufazy [111]
She estimated 586 to 600 and 754 to 800
800 - 600 is 200
6 0
3 years ago
) The jar has a total of 220 marbles. The table shows the estimates of three different students
EastWind [94]

Answer: 25%

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3 0
3 years ago
–40-7+3u simplified expression​
svet-max [94.6K]

Answer:

3u-47

Step-by-step explanation:

Just combine like terms, which for this case is the -40 and the -7. Hope this helps!

7 0
3 years ago
On a recent day 8 euros were worth 9 dollars and 24 euros were worth 24 dollars write an equation of the form y = kx
slavikrds [6]
<h3><u>Question:</u></h3>

On a recent day, 8 euros were worth $9 and 24 euros were worth $27. Write an equation of the form y = kx to show the relationship between the number of euros and the value in dollars.

<h3><u>Answer:</u></h3>

y = 1.125x is the equation to show the relationship between the number of euros and the value in dollars.

<h3><u>Solution:</u></h3>

Given that On a recent day 8 euros were worth 9 dollars and 24 euros were worth 24 dollars

Let "y" be the value in dollars

Let "x" be the number of euros

We have to write a equation in form of y = kx

<em><u>8 euros were worth 9 dollars</u></em>

"k" is found as follows:

k = \frac{\text{value in dollars}}{\text{number of dollars}}

k = \frac{9}{8}

Therefore, equation of y = kx is given as:

y = \frac{9}{8}x

y = 1.125x

To check the equation, use the another given value

24 euros were worth $27

y = 1.125 \times 24\\\\y = 27

Hence the equation y = 1.125x is correct    

5 0
3 years ago
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