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2 years ago

Three fourths plus 2

Mathematics

1 answer:

aleksley [76]2 years ago

3 0

Answer:

2.75

Step-by-step explanation:

3/4 (three fourths) plus 2 = 2.75!

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What is the surface area of the sphere?

Fantom [35]

Answer:

The surface area of the sphere is 314 mi².

Step-by-step explanation:

According to the given diagram, the diameter of the sphere is 10 mi.

If the radius is $r$ , then diameter $=2r$

So....

$2r=10\\ \\ r=\frac{10}{2}= 5$

Formula for the surface area of a sphere: $A_{S}= 4\pi r^2$

Plugging the value of $r$ into this formula, we will get...

$A_{S}=4\pi(5)^2\\ \\ A_{S}=4\pi(25)\\ \\ A_{S}=4(3.14)(25)\ \ [Using\ \pi=3.14]\\ \\ A_{S}=314$

So, the surface area of the sphere is 314 mi².

7 0

3 years ago

What three dimensions are needed to find the volume of a rectangular solid?

Katyanochek1 [597]

We need the length, the width and the height

7 0

3 years ago

PLEASE ANSWER ASAP!!! WHAT SHOULD 2.33 BE MULTIPLIED BY TO MAKE IT INTO A WHOLE NUMBRR??

mestny [16]

Answer:

2.331 = (2.33 × 100)(1 × 100) = 233100. As the numerator is greater than the denominator, we have an IMPROPER fraction, so we can also express it as a MIXED NUMBER, thus 233100 is also equal to 233100 when expressed as a mixed number.

Step-by-step explanation:

or mutilpy by 100

6 0

2 years ago

Read 2 more answers

Which of the following equations could you solve by first adding six and then dividing by negative three? 3x - 6 = -9 6 - 3x = -

mrs_skeptik [129]

Answer: $-3x-6=-9$

Step-by-step explanation:

The proccedure shown in the problem is applied to solve for x and calculate its value.

One of the equations shown in the problem is:

$-3x-6=-9$

To solve for x you must_

- Add 6 to both sides of the equations:

$-3x-6+6=-9+6$

$-3x=-3$

- Then you must divide by -3:

$\frac{-3x}{-3}=\frac{-3}{-3} \\x=1$

Then the answer is: $-3x-6=-9$

7 0

3 years ago

Write an equation of a parabola in vertex form. Vertex (2,-3) and passes through (0,5)

Strike441 [17]

The parabola equation in vertex form passes through (0,5) is $y=2(x-2)^{2}-3$

Solution:

Given that, vertex of a parabola is (2,-3) and the parabola passes through the point (0, 5)

We have to find the equation of parabola in vertex form.

The general form of parabola equation in vertex form is given as:

$y=a(x-h)^{2}+k$

Where (h, k ) is vertex and "a" is a constant

Here in our problem, h = 2 and k = - 3

By substituting the values in general form we get,

$\begin{array}{l}{y=a(x-2)^{2}+(-3)} \\\\ {\rightarrow y=a(x-2)^{2}-3}\end{array}$

Now, we know that it passes through (0, 5). So substitute x = 0 and y = 5

$\begin{array}{l}{\rightarrow 5=a(0-2)^{2}-3} \\\\ {\rightarrow a(-2)^{2}=5+3} \\\\ {\rightarrow 4 a=8} \\\\ {\rightarrow a=2}\end{array}$

So substituting the value of "a" we get,

$y=2(x-2)^{2}-3$

Hence, the parabola equation in vertex form is $y=2(x-2)^{2}-3$

5 0

3 years ago