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3 years ago

Problem: (5x^4 – 3x^3 + 6x) – (3x^3 + 11x^2 – 8x) Answer: 5x^4-6x^3 -11x^2 +14x

1 answer:

8 0

Combine the like terms by adding the coefficients,
->5x^4 can't add anything so leave it there,
->-3x^3 can add -3x^3 which gives you -6x^3,
->We can't do anything with -11x^2 so leave it there as well,
->6x add to -(-8x) gives you 14x,
You will get for your final answer is 5x^4-6x^3-11x^2+14x.

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1) Graph the following lines and using the graph determine several values of x for which the graph is positive (negative):

Aleksandr [31]

1) $y=-0.5x-2$

The graph of the above equation is attached in the attachment below.

For all the values from negative infinity to -4, the function is positive.

X ∈ (-∞,-4]

2) $y=-1.5x+3$

To find the x- intercept, plug y =0

$0=-1.5x+3$

$1.5x=3$

$x=2$

x intercept = (2,0)

To find the y- intercept, plug x=0

$y=-1.5(0)+3$

$y=3$

Y- intercept = ( 0,3)

3) $y=13-x$

Y- intercept = (0,13)

x- intercept = (13,0)

Area of triangle = $\frac{bh}{2}$

Area of triangle = $\frac{13\times13}{2}$

Area = $\frac{169}{2}$ sq unit.

4) The graphs of $y=-2x+7$ and $y=0.5x-5.5$ is attached in the attachment below.

The intersection point is ( 5,-3)

5) A = (-3,0)

B = (4,5)

C = (0,-4)

Slope of AB = $\frac{5-0)}{4-(-3)} =\frac{5}{7}$

Slope intercept of line $y=mx+b$

Where, m is the slope and b is the y- intercept.

Plugging point A and the slope in the y- intercept to find the value of b.

$0=\frac{5(-3)}{7} +b$

$b=\frac{15}{7}$

Equation of line AB: $y=\frac{5x}{7} +\frac{15}{7}$

Slope of BC = $\frac{-4-5}{0-4} =\frac{9}{4}$

Plug C = (0,-4)

$-4=0+b$

b=-4

equation of line BC= $y=\frac{9x}{4} -4$

Slope of line AC = $\frac{-4-0}{0--3} =\frac{-4}{3}$

Equation of line AC = $y=\frac{-4x}{3} -4$

Y intercept of AB = $(0,\frac{15}{7} )$

5 0

4 years ago

Read 2 more answers

plant a is 4.7 centimeters tall and growing at the rate of 3.5 centimeters a month. plant b is 5.2 centimeters tall and growing

olga55 [171]

Answer:

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Step-by-step explanation:

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3 0

3 years ago

Overnight rain has left 8 gallons of water in Juan's boat. Juan secures a small container and begins scooping the water out at a

GuDViN [60]

Answer:

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Step-by-step explanation:

4 0

3 years ago

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

True [87]

Answer:

the value of a, if points A and D belong to the x−axis and m∠BAD=60 degrees is 2/√3

Step-by-step explanation:

Trapezoid ABCD with height 2 unit contain Points A and D which may be A(-1,0) and D(5.0)

Vertex of parabola is the point where parabola crosses its axis

Let suppose A and D are two points then draw altitude on them CE where C is on AD

As height of altitude has been given that is 2 then

total angle = 180 degrees

m∠BAD=60 degrees

m∠CEA =180 - 60 -90

= 30

then the value for AE = 2/√3.

y=a(x+1)(x−5).

where 2/√3 is right of -1 and 2 unit above x-axis

5 0

3 years ago

the vertex of this parabola is (2,-1). When the x-value is 5 the y-value is 0.what is the coefficient of the squared expression

weeeeeb [17]

1/9
Here's the proper explanation:
Since the vertex is (2,-1), the original equation will look like this: y=a*(x-2)^2-1
When the substitution happens we get to this:
0=a*(5-2)^2-1 then 1=a*(5-2)^2 -> 1=a*9
So, a=1/9! Written in another form:
1/9x^2-4/9x+4/9-1

Hope could help :)

8 0

4 years ago