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3 years ago

Ne is done for you. 8, 10(3 + 5) = 10(3) + 10(5)

Mathematics

1 answer:

Luden [163]3 years ago

6 0

10(3 + 5) = 10(3) + 10(5) = 30 + 50 = 80

Another way to do it:

10(3 + 5) = 10(8) = 80

Your final answer is 80.

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Determine the area of the following shapes.<br> a. 144 in<br> b. 154 in<br> c. 164 in

ArbitrLikvidat [17]

A) 144 in

is your answer. good luck

6 0

2 years ago

If the bottom row as a result of sythetic division is 1 3 0 4 0, then the quotient is which of the following? Select one:

zmey [24]

The quotient of the synthetic division is x^3 + 3x^2 + 4

<h3>How to determine the quotient?</h3>

The bottom row of synthetic division given as:

1 3 0 4 0

The last digit represents the remainder, while the other represents the quotient.

So, we have:

Quotient = 1 3 0 4

Introduce the variables

Quotient = 1x^3 + 3x^2 + 0x + 4

Evaluate

Quotient = x^3 + 3x^2 + 4

Hence, the quotient of the synthetic division is x^3 + 3x^2 + 4

Read more about synthetic division at:

brainly.com/question/18788426

#SPJ1

3 0

2 years ago

Biologists tagged 139 fish in a lake on January 1, On February 1, they returned and collected a random sample

Bogdan [553]

Answer:

417 fish

Step-by-step explanation:

139/(10/30)=139*3=417

4 0

3 years ago

Simplify <br><br><br> 10 • 4 • 4 • 50 what is it lol

shusha [124]

0.0125 is your answer.
Hope this helps~!
~{Dunsforhands}

8 0

3 years ago

Read 2 more answers

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

7 0

3 years ago