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3 years ago

COMMON CORE REVIEW

Mathematics

1 answer:

masha68 [24]3 years ago

7 0

Answer:

146.9

Step-by-step explanation:

I'm not sure of the answer but if I'm wrong tell me I'll continue trying it is a pleasure to help you.

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Bobby earns $9 per hour plus commission. Last week he worked 32.5 hours

Nesterboy [21]

Answer:

Step-by-step explanation:

32.5*9=292.5

add the commission - $28.75

292.5+28.75= $321.25

8 0

1 year ago

Read 2 more answers

De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de

Sunny_sXe [5.5K]

Answer:

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

$M \propto \frac{r^{3}}{T^{2}}$

$M = k\cdot \frac{r^{3}}{T^{2}}$ (Eq. 1)

Donde:

$r$ - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

$T$ - Período oribital del satélite, medido en días.

$k$ - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

$M$ - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

$\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }$

$\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}$ (Eq. 2)

Donde:

$T_{M}$ , $T_{E}$ - Períodos orbitales de la Luna y la Tierra, medidos en días.

$r_{E}$ , $r_{M}$ - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

$M_{S}$ , $M_{E}$ - Masas del Sol y la Tierra, medidos en kilogramos.

Si $M_{E} = 75.97\times 10^{24}\,kg$ , $T_{E} = 365.3\,d$ , $T_{M} = 27.3\,d$ , $r_{M} = 3.84\times 10^{5}\,km$ y $r_{E} = 1.496\times 10^{8}\,km$ , entonces tenemos que la masa del Sol es:

$M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}$

$M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)$

$M_{S} = 2.509\times 10^{31}\,kg$

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

7 0

3 years ago

How are natural numbers, whole numbers and integers used in everyday life?

Nezavi [6.7K]

Natural numbers: Counting things! You look around your room and see an electronic device, then another, then another! You just counted to 3 using the natural numbers.

Whole numbers! You try to look for electronic devices and realise that they’re all gone. You have zero electronic devices, and you just used whole numbers.

You go online to find where your electronic devices went, and realise they were taken because you’re in debt to the bank so they took some of your stuff. You’re in negative numbers, and now you’ve used integers.

4 0

3 years ago

Someone help me plz !!!!!

Mrac [35]

Answer:

£1 = 25 hits

Step-by-step explanation:

Will get the equation is

$\frac{40}{1000} = \frac{1}{x}$

so, X=25

x = What we want to find

4 0

3 years ago

Please help me...............

denis-greek [22]

Answer:

Step-by-step explanation:

a(20ft)

b(46ft)

c(72.6mm)

6 0

2 years ago