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iragen [17]
3 years ago
6

Use the quotient property to rewrite log_(10)(x/(100,000))

Mathematics
1 answer:
padilas [110]3 years ago
7 0

Answer:

log_10(x) - log_10(100000)

Step-by-step explanation:

log_{10}(\frac{x}{100000} )\\log_{10}(x) -log_{10}(100000)\\

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–3(x – 14) + 9x = 6x + 42
sesenic [268]

Answer:

All real numbers

0 = 0

Step-by-step explanation:

Hope i'm right

Solving this equation results in the statement 0 = 0. Because this is a true statement, the equation has infinitely many solutions.

3 0
2 years ago
Read 2 more answers
You can represent an odd integer whith the expression 2n+1, where n is any integer . Write and solve an equation to find three c
oksian1 [2.3K]
Any odd number can be expressed by 2n+1.

For example,  

2n+1=111
2n=110
n=110/2=55

means that 111 is 2n+1 for n=55


Thus if an odd number is 2a+1, the next few numbers are as follows:

2a+1, 2a+2, 2a+3, 2a+4, 2a+5

So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.


Back to our problem: 

three consecutive odd numbers whose sum is 63 are:

(2n+1)+(2n+3)+(2n+5)=63

6n+9=63

6n=63-9=54

n=54/6=9


2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23


Answer: 19, 21, 23



5 0
3 years ago
Pls say hard<br>very hard​
Vlad [161]

Answer:

3

Step-by-step explanation:

7 0
2 years ago
the providence children muesuem installed a fence around the perimeter of the propety. the propety is a rectangle. one side is 3
mash [69]
Its a rectangle so two sides are equal and both sides that are opposite of each other are equal. So two sides are 37. Then you add them together to get 74, then subtract it from 164 to get 90 the rest of the fence length. Then divide it by two to get 45 which is the other side lengths, so it would be a 37 by 45 rectangle one side would be 37 while the other two are 45.
7 0
3 years ago
Underline all the ordered pairs (x,y) that are solutions to the equation y=2x+1.
Romashka [77]

Answer:

<u>(3,7)</u> (7,3) (−1,14) <u>(0,1)</u> <u>(12,25)</u>

<u>(5,11)</u> (0,12) (1,8) (12,0) <u>(−1,−1)</u>

Step-by-step explanation:

We have the following function:

y = 2x+1.

We are going to check if each ordered pair is a solution.

(3,7)

If when x = 3, y = 7, it is a solution.

y = 2x + 1 = 2(3) + 1 = 7

This ordered pair is a solution.

(7,3)

If when x = 7, y = 3, it is a solution.

y = 2x + 1 = 2(7) + 1 = 15

This ordered pair is not a solution.

(-1,14)

If when x = -1, y = 14, it is a solution.

y = 2x + 1 = 2(-1) + 1 = -1

This ordered pair is not a solution.

(0,1)

If when x = 0, y = 1, it is a solution.

y = 2x + 1 = 2(0) + 1 = 1

This ordered pair is a solution.

(12,25)

If when x = 12, y = 25, it is a solution.

y = 2x + 1 = 2(12) + 1 = 25

This ordered pair is a solution.

(5,11)

If when x = 5, y = 11, it is a solution.

y = 2x + 1 = 2(5) + 1 = 11

This ordered pair is a solution.

(0,12)

If when x = 0, y = 12, it is a solution.

y = 2x + 1 = 2(0) + 1 = 1

This ordered pair is not a solution.

(1,8)

If when x = 1, y = 8, it is a solution.

y = 2x + 1 = 2(1) + 1 = 3

This ordered pair is not a solution.

(12,0)

If when x = 12, y = 0, it is a solution.

y = 2x + 1 = 2(12) + 1 = 25

This ordered pair is not a solution.

(-1,-1)

If when x = -1, y = -1, it is a solution.

y = 2x + 1 = 2(-1) + 1 = -1

This ordered pair is a solution.

3 0
2 years ago
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