1.6 -1.6 +1.6 is the following
![A\left[\begin{array}{ccc}1&0&5\\0&-5&7\\0&3&-4\end{array}\right]](https://tex.z-dn.net/?f=A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%265%5C%5C0%26-5%267%5C%5C0%263%26-4%5Cend%7Barray%7D%5Cright%5D)
![B\left[\begin{array}{ccc}3&-5&3\\2&3&1\\4&1&-3\end{array}\right]](https://tex.z-dn.net/?f=B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%263%5C%5C2%263%261%5C%5C4%261%26-3%5Cend%7Barray%7D%5Cright%5D)
![Now,\\\\2B-A\\\\2\left[\begin{array}{ccc}3&-5&3\\2&3&1\\4&1&-3\end{array}\right]-\left[\begin{array}{ccc}1&0&5\\0&-5&7\\0&3&-4\end{array}\right]\\\\=\left[\begin{array}{ccc}6&-10&6\\4&6&2\\8&2&-6\end{array}\right] -\left[\begin{array}{ccc}1&0&5\\0&-5&7\\0&3&-4\end{array}\right]\\\\=\left[\begin{array}{ccc}5&-10&1\\4&11&-5\\8&-1&-2\end{array}\right]](https://tex.z-dn.net/?f=Now%2C%5C%5C%5C%5C2B-A%5C%5C%5C%5C2%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%263%5C%5C2%263%261%5C%5C4%261%26-3%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%265%5C%5C0%26-5%267%5C%5C0%263%26-4%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-10%266%5C%5C4%266%262%5C%5C8%262%26-6%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%265%5C%5C0%26-5%267%5C%5C0%263%26-4%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-10%261%5C%5C4%2611%26-5%5C%5C8%26-1%26-2%5Cend%7Barray%7D%5Cright%5D)
Row 1 column 2(a12)=-10
Hence,-10 is your answer.
Answer:
Yes
Step-by-step explanation:
The product of three polynomials will be a polynomial regardless of the signs of the leading coefficients of the polynomials.
Answer:
g(f(x)) = 2x - 2
Step-by-step explanation:
to evaluate g(f(x)) substitute x = f(x) into g(x)
g(f(x)) = g(2x + 1) = 2x + 1 - 3 = 2x - 2
Answer:
-8 < -4
Step-by-step explanation:
