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3 years ago

HIJK is a rectangle. HJ=x and IK=2x-7 Find the length of each diagonal

1 answer:

3 0

The diagonals of a rectangle are congruent so set them equal to each other to get x = 2x - 7. isolate the variable (0 = x - 7 — x = 7) to get x = 7. the diagonals are seven.

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Find the area of triangle ABC. Give your answer to 1 decimal place. Sine rule.

laiz [17]

Answer:

Solution,

In ∆ ABC

< A + <B + < C = 180°

or, 72 + 59 + <C = 180°

or, 131 + <C = 180°

or, <C = 180 - 131

< C = 49

Area of ∆ABC = 1/2 ab sin C

= 1/2 * 12 * 7 * sin 49

= 42 * sin 49

= 31.7 ( approximately)

Hope this helps...

Good luck on your assignment...

4 0

3 years ago

Select the correct answer from each drop-down menu. f(x) = x2 − 8x + 15 g(x) = x − 3 h(x) = f(x) ÷g(x) h(x) = . The domain of h(

9966 [12]

Answer:

all of them

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

I really am confused on how to write a proof.

kvasek [131]

Since ABCD is a parallelogram, the opposite sides will be parallel and equal,

$\begin{gathered} AB=CD \\ BC=AD \end{gathered}$

Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,

$\begin{gathered} \angle CAD=\angle ACB\text{ (Alternate Interior Angles)} \\ BC=AD\text{ (Opposite sides of parallelogram)} \\ \angle ADB=\angle CBD\text{ (Alternate Interior Angles)} \end{gathered}$

So by the ASA criteria, the triangle AED is congruent to the triangle CEB,

Then the corresponding parts of the triangles will be equal,

$\begin{gathered} AE=CE \\ BE=DE \end{gathered}$

Hence Proved.

8 0

1 year ago

This composite shape is a rectangle with a semicircle attached on one end. The diameter of the semicircle is 6 feet.

Ugo [173]

As we can see on the picture we have a rectangle and half of circle.

The areas for half circle and rectangle are:

$A_{rectangle}=a\cdot b \\A_{halfcircle}=\frac{A_{circle}}{2}=\frac{\pi r^2}{2}$

The area of the figure is the sum of the area of half circle and rectangle. Also the height of a rectangle (6ft) is a diameter of a half circle therefore the radius of half circle is 6ft ÷ 2 = 3ft.

Now we calculate the areas.

$A_{rectangle}=10\cdot 6=\underline{60} \\A_{halfcircle}=\frac{3.14\cdot3^2}{2}=\underline{14.13} \\A_{total}=A_{rectangle}+A_{halfcircle} =60+14.13=\boxed{74.13\approx74}$

The area of the figure is approximately 74ft squared.

Hope this helps.

r3t40

3 0

3 years ago

Read 2 more answers

Find y so that (-2, y) is a solution to 3x + 5y=8

podryga [215]

Answer:

y = $\frac{14}{5}$

Step-by-step explanation:

Substitute x = - 2 into the equation and solve for y

3(- 2) + 5y = 8, that is

- 6 + 5y = 8 ( add 6 to both sides )

5y = 14 ( divide both sides by 5 )

y = $\frac{14}{5}$

5 0

3 years ago

HIJK is a rectangle. HJ=x and IK=2x-7 Find the length of each diagonal​

HIJK is a rectangle. HJ=x and IK=2x-7 Find the length of each diagonal