For cylinder
d=10m
So r=5m
h=5m
volume=pi×r^2×h
=3.14×5×5×5
=3.14×125
=392.5m^3
So option a is correct.
Answer:
a=1
b= -6
c=48
Step-by-step explanation:
x^2=6(x-8)
x^2=6x-48
x^2-6x+48
a,b are the coefficients of x^2 and x
c is the constant value present
Therefore it is basically written as ax^2+bx+c
and comparing with the answer x^2-6x+48,
a=1, b= -6, c=48
Answer:
all values of b
Step-by-step explanation:
6b < 36 or 2b + 12 > 6.
First solve the one on the left
6b < 36
Divide by 6
6b/6 < 36/6
b <6
Then solve the one on the right
2b + 12 > 6
Subtract 12 from each side
2b+12-12 >6-12
2b >-6
Divide by 2
2b/2 >-6/2
b >-3
b<6 or b >-3
Rewriting
b>-3 or b<6
b > -3 is an open circle at -3 with a line going to the right
b < 6 is an open circle at 6 with a line going to the left
The or means we add the lines together
We have a line going from negative infinity to infinity
all values of b
The image isn’t working, just letting you know
By Question it's given that the sum of two numbers is 15 . And we need to find out the numbers. So ,
<u><em>Let </em><em>us </em><em>take</em><em> </em><em>:</em><em>-</em><em> </em></u>
- First number = x
- Second number = x + 1
<em><u>According</u></em><em><u> to</u></em><em><u> the</u></em><em><u> Question</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>
<em><u>Therefore</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>
- First number = 7
- Second number = 8
<u>Hence</u><u> the</u><u> </u><u>two </u><u>numbers</u><u> </u><u>are </u><u>7</u><u> </u><u>and </u><u>8</u><u>. </u>