Answer:
<h2>
31.7 cm^2</h2>
Solution,
In ∆ ABC
< A + <B + < C = 180°
or, 72 + 59 + <C = 180°
or, 131 + <C = 180°
or, <C = 180 - 131
< C = 49
Area of ∆ABC = 1/2 ab sin C
= 1/2 * 12 * 7 * sin 49
= 42 * sin 49
= 31.7 ( approximately)
Hope this helps...
Good luck on your assignment...
Since ABCD is a parallelogram, the opposite sides will be parallel and equal,

Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,

So by the ASA criteria, the triangle AED is congruent to the triangle CEB,
Then the corresponding parts of the triangles will be equal,

Hence Proved.
As we can see on the picture we have a rectangle and half of circle.
The areas for half circle and rectangle are:

The area of the figure is the sum of the area of half circle and rectangle. Also the height of a rectangle (6ft) is a diameter of a half circle therefore the radius of half circle is 6ft ÷ 2 = 3ft.
Now we calculate the areas.

The area of the figure is approximately 74ft squared.
Hope this helps.
r3t40
Answer:
y = 
Step-by-step explanation:
Substitute x = - 2 into the equation and solve for y
3(- 2) + 5y = 8, that is
- 6 + 5y = 8 ( add 6 to both sides )
5y = 14 ( divide both sides by 5 )
y = 