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dimaraw [331]
3 years ago
12

The formula represents the surface area S of a cube with side lengths x. (choices in photo)

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0
We have the following expression:
 S = 6x ^ 2
 We must clear x from the equation.
 For this, we follow the following steps:
 Step 1)
 
Pass 6 to divide:
 S / 6 = x ^ 2
 Step 2)
 
Square root on both sides:
 +/- root (S / 6) = x
 Step 3)
 
Multiply numerator and denominator by 6:
 x = + / - root (6S / 6 * 6)
 Step 4)
 Rewrite expression:
 x = + / - root (6S / 36)
 Step 5)
 
Take root to denominator:
 x = + / - (root (6S)) / 6
 Answer:
 
x = + / - (root (6S)) / 6
 
(option 2)
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3 years ago
A bill from a plumber was $306 The plumber charged $150 for parts and $52 per hour for labor. How long did ths plumber work at h
ludmilkaskok [199]
We can make an equation from this.
Our intial value is 150 for parts, and he works for 52 dollars an hour.
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c = 150 + 52h.
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3 years ago
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SIZIF [17.4K]
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The average maximum monthly temperature in Campinas, Brazil is 29.9 degrees Celsius. The standard deviation in maximum monthly t
velikii [3]

Answer:

3.84% of months would have a maximum temperature of 34 degrees or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29.9, \sigma = 2.31

What percentage of months would have a maximum temperature of 34 degrees or higher?

This is 1 subtracted by the pvalue of Z when X = 34. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 29.9}{2.31}

Z = 1.77

Z = 1.77 has a pvalue of 0.9616

1 - 0.9616 = 0.0384

3.84% of months would have a maximum temperature of 34 degrees or higher

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