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kompoz [17]
3 years ago
14

How do sketch this?​

Mathematics
1 answer:
lara [203]3 years ago
7 0

Answer:

You would graph it like this.

Step-by-step explanation:

Here's a tip! Use demos! It's free and you can graph equations and points and it tell you how to graph it.

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I needs help please and tank chu
PIT_PIT [208]

9514 1404 393

Answer:

  C  {2, 4, 9, 16}

Step-by-step explanation:

The domain is the list of numbers at the tails of the arrows.

The range is the list of numbers at the heads of the arrows: {2, 4, 9, 16}.

5 0
3 years ago
34 = 10 + 4q<br> Solve<br> Need help
LiRa [457]

Simplifying

34 = 10 + 4q

Solving

34 = 10 + 4q

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-4q' to each side of the equation.

34 + -4q = 10 + 4q + -4q

Combine like terms: 4q + -4q = 0

34 + -4q = 10 + 0

34 + -4q = 10

Add '-34' to each side of the equation.

34 + -34 + -4q = 10 + -34

Combine like terms: 34 + -34 = 0

0 + -4q = 10 + -34

-4q = 10 + -34

Combine like terms: 10 + -34 = -24

-4q = -24

Divide each side by '-4'.

q = 6

Simplifying

q = 6

hope this helps please mark brainliest

6 0
3 years ago
The rate of change of the mass, A, of salt at time t is proportional to the square of the mass of salt present at time t. Initia
Brums [2.3K]

Answer:

(a) -dA/dt = kA², A₀ = 10

(b) A =10/(1+ kt)

(c) t > 60 h

Step-by-step explanation:

(a) Find the IVP

A differential equation with an initial condition y₀ = f(x₀) is called an initial value problem.

The rate of decrease of A is proportional to A², and A₀ = 10, so the IVP is

-dA/dt = kA², A₀ = 10

(b) Solve the IVP

\begin{array}{rcl}-\dfrac{\text{d}A}{\text{d}t} & = & kA^{2}\\\\\dfrac{\text{d}A}{A^{2}} & =&-k\text{d}t\\\\-\dfrac{1}{A} & = & -kt + C\\\\\dfrac{1}{A} & = & kt + C\\\\\end{array}

Apply the initial condition: A₀ = 10 (when t = 0)

\dfrac{1}{10} = C\\\\\dfrac{1}{A} = kt + \dfrac{1}{10}\\\\\dfrac{10}{A} = 10kt + 1\\\\\mathbf{A} = \mathbf{\dfrac{10}{1+ kt}}

(c) Find the time when A(t) < 1

(i) Find the value of k (A₁₀ = 4)

\begin{array}{rcl}A& =&\dfrac{10}{1+ kt}\\\\4 & =& \dfrac{10}{1 + 10k}\\\\4 + 40 k & = & 10\\\\40k & = & 6\\k & = & 0.15\\\end{array}\\\\\mathbf{A} =\mathbf{ \dfrac{10}{0.15t + 1}}

(ii) Find t when A < 1

\begin{array}{rcl}A(t) & < & 1\\\dfrac{10}{0.15t + 1} & < & 1\\\\10 & < & 0.15t + 1\\9 & < & 0.15t\\t & > & 60\\\\\end{array}\\\mathbf{A < 1} \textbf{ when }\mathbf{ t >60}

The figure below shows the graph of A vs t.

6 0
3 years ago
Find the value of x in the image
Ber [7]

Answer:

50

Step-by-step explanation:

a pentagon has a total of 540 degrees

105, 115, 110, 180-2x, 180-3x are the interior angles (subtract each from 180 because they're on lines)

540= 105+115+110+(180-2x)+(180-3x)

540=330 +(180-2x)+(180-3x)

210=360-5x

-150=-5x

50=x

4 0
3 years ago
22% of _ peaches is 11 peaches
Neko [114]
I’m pretty sure it’s 50 peaches
3 0
3 years ago
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