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Alenkinab [10]
3 years ago
12

Please correct my work and show your work if I MESSED up please

Mathematics
1 answer:
sertanlavr [38]3 years ago
4 0

Hello from MrBillDoesMath!

Answer:

Your answer is correct. (You have earned the unofficial title of Genius, Jr. );


Discussion:

Whew! This is a long problem. Let me see what I get and compare it to your answer. First each of the 3 terms contains the sqrt(yz) so let's factor that terms out. You equations equals

sqrt(yz) (  sqrt(108) +  3 sqrt(98) + 2 sqrt(75) )                           (A)

Hmm....  let's look at the prime factorizations....

108 = 3 * 36 = 3 * (4*9) = 3 * 2^2* 3^2  

98   = 2 * 49 = 2 * 7^2

75   = 3 * 25 = 3 * 5^2

So (A)  =

sqrt(yz)  ( 6 sqrt(3) + 3*7 sqrt(2) +  2*5 sqrt(3) ) =

sqrt(yz)  (  ( 6 + 2*5) sqrt(3) + 21 sqrt(2) ) =

sqrt(yz) ( (6 + 10) sqrt(3) + 21 sqrt(2))  =

sqrt(yz) ( 16 sqrt(3) + 21 sqrt(2) )


Our answers agree!  



Thank you,

MrB

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CarcuratOS 11.A credit card charges an annual rate of 18% compounded monthly. This month's bill is Rs. 35,000... Suppose that yo
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Answer:

FIRST QUESTION

It will pay the bill after 7.45 = rounding 8 months, being the last payment less than 5,000

The total interest for the period will be 2,263.04

SECOND QUESTION The rate will be 6%

Step-by-step explanation:

for the first part, we should calculate the time it takes to an ordinary annuity of 5,000 to have a present value of 35,000 at discount rate of 18%

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 5,000

time n

rate 0.015

PV $35,000.0000

5000 \times \frac{1-(1+0.015)^{-n} }{0.015} = 35000\\

We work out the formula:

(1+0.015)^{-n}= 1-\frac{35000\times0.015}{5000}

We solve the right side of th formula

and then apply logarithmics properties:

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It will pay the bill after 8 months.

Total Interest: we will build the loan schedule:

         Bill          Interest    Cuota&Amortization

1      35000        525&      5000          4475

2     30525        457.88    5000         4542.12

3     25982.88  389.74     5000        4610.26

4     21372.62   320.59     5000         4679.41

5     16693.21   250.4       5000          4749.6

6     11943.61    179.15       5000          4820.85

7      7122.76    106.84     5000           4893.16

8       2229.6    33.44      2263.04       2229.6

Total              2263.04   37263.04       35000

The total interest for the period will be 2,263.04

<u>Second question </u>we will solve for the rate at which a capital of 3,000 returns 5,372.54 after 10 years

Principal \: (1+ r)^{time} = Amount

Principal 30,00.00

Amount = 5,372.54

time 10.00

rate ?

3,000 \: (1+ r)^{10} = 5,372.54

r = \sqrt[10]{5,372.54/3,000} - 1

r = 0.059999939 = 0.06 = 6%

4 0
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