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3 years ago

Please correct my work and show your work if I MESSED up please

Mathematics

1 answer:

sertanlavr [38]3 years ago

4 0

Hello from MrBillDoesMath!

Answer:

Your answer is correct. (You have earned the unofficial title of Genius, Jr. );

Discussion:

Whew! This is a long problem. Let me see what I get and compare it to your answer. First each of the 3 terms contains the sqrt(yz) so let's factor that terms out. You equations equals

sqrt(yz) ( sqrt(108) + 3 sqrt(98) + 2 sqrt(75) ) (A)

Hmm.... let's look at the prime factorizations....

108 = 3 * 36 = 3 * (4*9) = 3 * 2^2* 3^2

98 = 2 * 49 = 2 * 7^2

75 = 3 * 25 = 3 * 5^2

So (A) =

sqrt(yz) ( 6 sqrt(3) + 3*7 sqrt(2) + 2*5 sqrt(3) ) =

sqrt(yz) ( ( 6 + 2*5) sqrt(3) + 21 sqrt(2) ) =

sqrt(yz) ( (6 + 10) sqrt(3) + 21 sqrt(2)) =

sqrt(yz) ( 16 sqrt(3) + 21 sqrt(2) )

Our answers agree!

Thank you,

MrB

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a car travels along a straight road to the east for 150 meters in 4 seconds and west for 50 meters in one second

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2 years ago

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

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If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

3 years ago

A bucket holds b liters of water. But a jar holds 8 fewer liters than the bucket. How many times can the bucket hold than the ja

kykrilka [37]

Answer:

b / (b - 8)

Step-by-step explanation:

Given that :

Litres of water held by bucket = b

Jar holds 8 litres fewer than bucket; hence, litres held by jar = b - 8

The number of times bucket can hold than jar is :

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2 years ago

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Answer:

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Step-by-step explanation:

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Multiply.

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Answer:

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