Write an equation for a parabola with x-intercepts (-4,0) and (5,0) which passes through the point (3. – 28).

1 answer:

5 0

Answer:

y=a(x-p)(x-q)

y=a(x+2+√2)(x+2-√2)

passing through point (-1,1)

substitute

1=a(-1+2+√2)(-1+2-√2)

1=a(1+√2)(1-√2)

1=a(1-2)

1=a(-1)

a=1/(-1)

a=-1

y=-(x+[2+√2])(x+[2-√2])

y=-(x2+4x+2)

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<h3>Answer:</h3>

x=2

<h3>Solution:</h3>

In order to isolate x, we should first of all take the square root of both sides.
If we take the square root of the left-hand side, we will get
$x-\displaystyle\frac{1}{2}$
How about the right-hand side? Well, we should take the square root of the numerator (9) and the denominator (4)
So we have
$x-\displaystyle\frac{1}{2} =\frac{3}{2}}$
Move -1/2 to the right:
$x=-\displaystyle\frac{3}{2} +\frac{1}{2}$
$x=\displaystyle\frac{4}{2}$
x=2