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erastova [34]
3 years ago
5

Solve for X Tysm!! I need help ASAP

Mathematics
1 answer:
amm18123 years ago
6 0

X-4/3 <= 5

Multiply both sides by 3:

X-4 <= 15

Add 4 to both sides:

X <= 19

The answer is the third one.

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Problem: a circle is inscribed in a square. The squares perimeter is 16 times the square root of 6. What is the probability of s
Oksi-84 [34.3K]
I got 21% at selecting a point outside.
Explanation: Since the perimeter is 16sqrt (6), each side must be 4sqrt (6)
This also means that the diameter is 4sqrt (6).

To find the area of a circle, we need to find the radius (2sqrt (6)).
Area of circle is pi × (2sqrt (6))^2 = 24pi or approximately 75.4 units^2
Area of square is 4sqrt (6)^2 = 96

Thus, let's take the area of the circle and subtract that from the area of our square to yield approx. 20.6 units^2
and now divide through by 96 to yield 21%
8 0
4 years ago
The table shows the maximum and minimum depths of two submarines. Find the range of depths for each submarine. Then determine wh
JulsSmile [24]

Answer:

Range A = 386ft

Range B = 427ft

B has the larger range.

Explanation:

To find the range, find the difference between the minimum and maximum depths for each submarine. Remember that your answer will be positive.

Sub A:

-146ft - (-532ft) = 386 ft

Sub B:

-194ft - (-621ft) = 427 ft

Submarine B has a larger range.

7 0
4 years ago
If the lengths of two sides of a triangle are 6 and 8 the length of the third side may be
tangare [24]
Depends on the angle sir
6 0
3 years ago
40 points” help HLP HL
cestrela7 [59]

Answer:

D: {(-5, -4, 2, 2, 5)}

R: {(-6, 3, 4, 1, 5)}

The relation is NOT a function.

Step-by-step explanation:

By definition:

A relation is any set of ordered pairs, which can be thought of as (input, output).

A function is a <em><u>relation</u></em> in which no two ordered pairs have the same first component (domain/input/x value) and different second components  (range/output/y value).

Looking at the given points in your graph, and in listing down the domain and range, we can infer that the relation is not a function because there is an x-value (2) that has two corresponding y-values: (2, 4) (2, 1).

Another way to tell if a given set of points in a graph represents a function by doing the "Vertical line test." The graph of an equation represents y as a function of x if and only if no vertical line intersects the graph more than once. Looking at the attached image, I drew a vertical line over points (2, 4) (2, 1). The vertical line intersects the two points, which fails the vertical line test. This is an indication that the given relation is not a function.

8 0
3 years ago
100 POINTS PLEASE HELP ASAP!!!! BTW I'm adding an attachment so dont answer until u see the question :)
nordsb [41]

\bf \cfrac{2}{5}\cdot \cfrac{3}{8}\implies \cfrac{\stackrel{1}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{5}\cdot \cfrac{3}{\underset{4}{~~\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{3}{20}

4 0
3 years ago
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