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erastova [34]
3 years ago
5

Solve for X Tysm!! I need help ASAP

Mathematics
1 answer:
amm18123 years ago
6 0

X-4/3 <= 5

Multiply both sides by 3:

X-4 <= 15

Add 4 to both sides:

X <= 19

The answer is the third one.

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in the xy-plane, the line x + y=k, where k is a constant, is tangent to the graph of y=x^2+3x+1. What is the value of k?
Sholpan [36]
When a line and a curve are tangent to each other, they are joined together by 1 point (x,y). So, you equate both equations either in terms of x or y. For this problem, let's equate in terms of y.

y = k - x
y = x² + 3x + 1

k - x = x² + 3x + 1
k = x² + 3x + x + 1
k = x² + 4x + 1

This would be the value of k. Since we are not given the common point, it can only be expressed in terms of x or y.
3 0
4 years ago
For the inverse variation equation xy = k, what is the constant of variation, k, when x = –3 and y = –2?
Dovator [93]

Answer:

6 =k

Step-by-step explanation:

Given the equation for inverse variation

xy = k

We know x=-3 and y = -2

Substituting these values in

(-3) (-2) = k

6 =k

7 0
3 years ago
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Need helpppppp pleaseeeeee help mememememee
LuckyWell [14K]

Answer:

Step-by-step explanation:

v=3+1.5x7

v= 13.5 m/s

8 0
3 years ago
Two cars, car X and car Y , start moving from the same point P on a cross intersection. Car X is travelling east and car Y is tr
agasfer [191]
Let the distance traveled by car X be x km 
<span>let the distance traveled by car Y by y km </span>
<span>their paths form a right-angled triangle. </span>
<span>Let the distance between them be D km </span>
<span>D^2 = x^2 + y^2 </span>
<span>2D dD/dt = 2x dx/dt + 2y dy/dt </span>
<span>dD/dt = (x dx/dt + y dy/dt)/D </span>

<span>at the given case: </span>
<span>x = 60, y = 80 , dx/dt = 80, dy/dt = 100 </span>
<span>D^2 = 60^2 + 80^2 = 10000 </span>
<span>D = 100 </span>

<span>dD/dt = (60(80) + 80(100))/100 </span>
<span>= 128 </span>
5 0
3 years ago
HELP THIS IS DUE TODAY!!!!!! AHHHHHH
belka [17]

Answer:

260 / 5 = 52

Step-by-step explanation:

give brainliest please

8 0
3 years ago
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