Question

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Answer 1

Answer:

$\frac{ {x}^{2} + - 4x - 2 }{ {x}^{2} - 4 } + \frac{8x + 6}{{x}^{2} - 4} \\ = \frac{ {x}^{2} + - 4x + 8x - 2 + 6 }{ {x}^{2} - 4 } \\ = \frac{ {x}^{2} + 4x + 4 }{ {x}^{2} - 4 } \\ = \frac{ {(x + 2)}^{2} }{(x - 2)(x + 2)} \\ = \frac{x + 2}{x - 2}$