Given that a company budgeted 5 1/4 hours to complete a project, determine how much time they spent on research if they spent 1/3 of the total budget.
First, convert the budget from hours into minutes.
5 1/4 hours = 315 minutes
1 hour = 60 min
1/4 hour = 15 min
60 x 5 = 300
300 + 15 = 315
Then, divide the minutes by 3 or multiply it by 1/3.
315 / 3 = 105
315 x 1/3 = 105
Lastly convert to a mixed number.
1 3/4 hour
Thus, the company plans to spend 1 3/4 hours or 1 hour and 45 minutes on research.
Answer:
$0.64
Step-by-step explanation:
Unit price is the cost of a single metre of ribbon
5.12/8=0.64
Answer:
172,000
Step-by-step explanation:
it was kinda obvious
Answer:
a) For the 90% confidence interval the value of 
and 
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
b) For the 99% confidence interval the value of 
and 
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
Part a
For the 90% confidence interval the value of and , with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
Part b
For the 99% confidence interval the value of and , with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Answer:
the independent variable is the # of runners while the dependent is the # of water bottles
Step-by-step explanation:
