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ZanzabumX [31]
4 years ago
6

If you measure the mass of a model car to be 230 grams, but the actual mass is 218 grams, what is your percent error?

Physics
1 answer:
konstantin123 [22]4 years ago
8 0

Mass of a model car you measured = 230 grams

Actual mass = 218 grams

Percent error = ?

First subtract the actual value from the value you measured,

230 grams – 218 grams = 12 grams

Now divide 12 grams by the actual mass that is 218 grams:

12 / 218 = 0.055                             

Now multiply 0.055 with 100 to get the percent error;

0.055 x 100 = 5.5%

So, the Percent error is 5.5%.

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Answer: Water is absorbed in the intestine through gradient transport. The correct option is E.

Explanation:

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- As sodium is pumped out of cells an osmotic gradient is formed across apical cell membrane, this helps to osmotically drive water across the epithelium. Therefore water is absorbed in the intestine through the osmotic gradient created by sodium absorption. I hope this helps. Thanks.

6 0
3 years ago
1) A change in momentum is the result of an
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Calculate the density of each ball. Use the formula
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After driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average
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Answer:

Incomplete Question

Explanation:

String constant is not stated

I'll solve this in a general way.

At the end of my explanation, I'll assume any value for string constant.

The total weight on the taptap : Weight of people + Weight of goats + Weight of chickens + weight of banana

= (25 * 66) + (3 * 15) + (5 * 3) + 25 = 1735 kg

The gravitational force exerted on the taptap

Fig = m*g

where m = the total mass 1735kg

and g = 9.8m/s²

Hooke's law of Elasticity states that

Fs = Kx

Where Fs = spring force

k = spring constant

x = spring stretch or compression

Since Fs = Fg

So, Kx = mg

Make x the subject of the formula

x = mg/k --------------- This is the general way of solving for spring compressor in cases like this

I'll replace m and g with their values, respectively.

Because, the spring constant (k) is omitted in the question, I'll assume it to be 30000

x = 1735 * 9.8/30000

x = 17003/30000

x = 0.566767 metres

x = 0.57 metres ------------- Approximated

In conclusion, the spring compression is 0.57 metres if the spring constant is 30000

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