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harina [27]
4 years ago
13

The _____ of a mechanical wave is a direct measure of its energy.

Physics
1 answer:
KiRa [710]4 years ago
6 0

I think it's amplitude

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What are the output waveforms of the following waves, after passing through a transformer?
Ber [7]
The output waveforms after passing through the transformer actually depend on the type of transformer used. It could either be a step-up transformer (steps voltage up), or a step-down transformer (steps voltage down). Both transformers have an output voltage in a form of a sine wave.
8 0
3 years ago
A wave of frequency 90 mega in 3 micro seconds. Calculate its wave length. hertz travels 6 km​
gladu [14]

the wavelength is 2.2m

wavelength can be calculated by formula wavelength = velocity / frequency so here first we need to find the velocity so velocity is distance travelled/time taken that 2 X 10^8 m/s now wavelength is =  2 X 10^8/ 90=2.2m.

Waves are signals that can go through various media, including wire in the case of an electrical AC current, water, light, and other media. The separation between two identical points on a sinusoidal wave is known as the wavelength. You can determine how long there is between each wave's peak and each wave's trough if you know the frequency of the wave moving through the medium.

To learn more about wavelength:

brainly.com/question/13533093

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3 0
2 years ago
A person observing a flame is interested in the types of electromagnetic waves with slightly shorter and slightly longer wavelen
Nadya [2.5K]

Answer:

Ultra violet rays and infrared rays

Explanation:

The electromagnetic radiation in the order of increasing wavelength is given as

Gamma rays

X rays

Ultra violet rays

Visible radiation

Infrared rays

Microwaves

radiowaves

So, the radiations having wavelength more than the visible radiation are infrared radiations and the radiations which having the wavelength less then the visible radiation is Ultraviolet rays.

So, we observe ultra violet radiations and infrared radiations.

3 0
4 years ago
Light passes through a 0.15 mm-wide slit and forms a diffraction pattern on a screen 1.25 m behind the slit. The width of the ce
Elena L [17]

Answer:

The value is  \lambda =  900 \ nm

Explanation:

From the question we are told that

   The width of the slit is  a =  0.15 \ mm = 0.00015 \  m

     The distance of the screen from the slit is D = 1.25 m

      The width of the central maximum is y =  0.75 \ cm  = 0.0075 \ m

Generally the width of the central maximum is mathematically represented as

         y   =  \frac{m *  D  *  \lambda}{a}

Here  m is the order of the fringe and given that we are considering the central maximum, the order will be  m =  1  because the with of the central maximum separate's the and first maxima

So

        \lambda     =     \frac{a y}{ m *  D }

=>     \lambda     =     \frac{ 0.000015 *  0.0075}{ 1  *  1.2 }

=>     \lambda     =   900 *10^{-9} \  m

=>      \lambda =  900 \ nm

6 0
3 years ago
Choose ne
Tju [1.3M]

Answer:

diamond

Explanation:

im not 100% sure so my bad if im wrong

6 0
3 years ago
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