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3 years ago

An object falling straight down without air resistance is said to be exhibiting

Physics

1 answer:

Tanzania [10]3 years ago

6 0

Answer:

Explanation:

If the object is falling straight down it is in free fall. The difference between that and two-dimensional motion is that 2D motion is parabolic (projectile)

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A toy airplane, flying in a horizontal, circular

Goshia [24]

Answer:

8.4 m/s

Explanation:

The toy completes 10 circle in 30 seconds. So its frequency of revolution is

$f=\frac{10}{30 s}=0.33 Hz$

The periof of revolution is the reciprocal of the frequency, so

$T=\frac{1}{f}=\frac{1}{0.33 Hz}=3 s$

The radius of the circular path is

r = 4.0 m

So the total distance covered by the toy in one circle is the length of the circumference:

$2\pi r$

And so the average speed is

$v=\frac{2\pi r}{T}=\frac{2\pi (4.0 m)}{3 s}=8.4 m/s$

4 0

3 years ago

Read 2 more answers

A ball falling through the air has what?

AysviL [449]

A ball falling through the air has a mass, a density, a volume...it is facing air resistance and is being acted on by gravity...it is accelerating and gaining velocity...and it is increasing in kinetic energy.
I suppose out of all those the biggest thing the ball has in this case is ENERGY. There are two main types to focus on...

Kinetic Energy - The further the ball fall the more KE it has...until terminal velocity is reach, then KE would become constant.
Potential Energy - Conversely to that of KE, the further the ball falls the less PE it will have.

<em>Heat/Thermal Energy is technically also present due to the friction from the air resistance, but the transfer of energy between the air and ball is quite complex and not necessary important for basic physics.
</em>
The question itself seem kind of vague and open ended, but I could just be viewing it the wrong way.
Comment if you need more help!

8 0

3 years ago

calculate the currrent passing acrooss a bulb if it has a resistane of 15 ohms and a potentinal difference of 6v is applied acro

lawyer [7]

V = IR

6 V = I × 15 Ohms

I = 6 V : 15 Ohms

I = 0,4 A

#LearnWithEXO

4 0

2 years ago

A revolutionary war cannon, with a mass of 2260 kg, fires a 15.5 kg ball horizontally. The cannonball has a speed of 109 m/s aft

Anton [14]

Answer:

The gain in velocity is 0.37m/s

Explanation:

We need solve this problem though the conservation of momentum. That is,

$m_1 v_1 = m_2 v_2$

$m_1=2260Kg\\m_2=15.5Kg\\v_2= 109m/s$

Using the equation to find $v_1$ ,

$v_1=\frac{m_2 v_2}{m_1}\\v_1=\frac{15.5*109}{2260}\\v_1= 0.7475$

Using the conservation of energy equation, we have,

$KE= \frac{1}{2}m*v^2$

$KE_{cball}=\frac{1}{2}(15.5)(109)^2=92077.75J$

$KE_{cannon}=\frac{1}{2}(2260)(0.7475)^2=631.39J$

$Total KE= 92077.75+13425530=92708.9J$

Now this energy over the cannonball

$KE=\frac{1}{2}m*v_2^2$

$92708.9=\frac{1}{2}15.5v_2^2$

$V_2 = 109.37m/s$

The gain in velocity is 0.37m/s

4 0

3 years ago

Auroras are frequently seen

Kipish [7]

Auroras are frequently seen : B. After solar flares
The Aurora is created by an ongoing influx of particles into the Earth's existing magnetic field,
This particles originated from the Sun as part of Solar wind

hope this helps

3 0

2 years ago