Step-by-step explanation:
d(t) = -16t² + 96t + 112
A) The quarter's initial height is at t = 0.
d(0) = -16(0)² + 96(0) + 112
d(0) = 112
The quarter is tossed from a height of 112 feet.
B) The maximum height is at the vertex of the parabola, which is at x = -b/(2a).
t = -(96) / (2 × -16)
t = 3
The quarter reaches its maximum height after 3 seconds.
C) d(3) = -16(3)² + 96(3) + 112
d(3) = 256
The quarter reaches a maximum height of 256 feet.
D) When the quarter lands in the water, d(t) = 0.
0 = -16t² + 96t + 112
0 = t² − 6t − 7
0 = (t + 1) (t − 7)
t = -1 or 7
Since t can't be negative, t = 7. So the quarter lands in the water after 7 seconds.
<span>5x4 = 20
</span><span>5x1/4 = 5/4 or = 1.25
so 20 > 1.25 then </span><span>5x4 is greater than 5x1/4</span>
Answer: 7.3
Step-by-step explanation:
The square root of 53 is 7.28010988928, and if you round that number to the nearest tenth it is 7.3.
It should be 10. you add up ab and bc
<h2>
Answer: 816 years</h2>
This problem can be solved using the <u>Radioactive Half Life Formula:
</u>
<u />
(1)
Where:
is the final amount of the material
is the initial amount of the material
is the time elapsed (the quantity we are asked to find)
is the half life of americium-241
Knowing this, let's find from (1):
Applying natural logarithm in both sides:
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<u>Finally:</u>
