Answer:
x = 0 or 1 or -2
Step-by-step explanation:
x(x^3-3x+2)=0
x(x-1)^2 * (x+2)0
so x = 0 or 1 or -2
there is no imaginary solutions
Plug in 0 into x of the equation y=2x+3, solve it, then take that answer and use that as your y then plug in the answer for y and solve for x. (i realized i am very bad at explaining this over this. Sorry I tried)
Answer:
First, a absolute value function is something like:
y = f(x) = IxI
remember how this work:
if x ≥ 0, IxI = x
if x ≤ 0, IxI = -x
Notice that I0I = 0.
And the range of this function is all the possible values of y.
For example for the parent function IxI, the range will be all the positive reals and the zero.
First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.
Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:
y ≥ A
Or all the real values equal to or larger than A.
if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:
y ≤ A
Or "All the real values equal to or smaller than A"
2? because you add 6 and 3 together and get 9 then you subtract 11 by 9 and get 2
