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Julli [10]
3 years ago
10

Find the measure of angle b

Mathematics
1 answer:
Andrew [12]3 years ago
3 0

Answer:

b = 116⁰

we have:

b + 64⁰ = 180⁰

<=> b = 180⁰ - 64⁰

<=> b = 116⁰

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If the diagonal of a square is approximately 12.73, what is the length of its sides?
Alja [10]

Answer:

The length of the sides of the square is 9.0015

Step-by-step explanation:

Given

The diagonal of a square = 12.73

Required

The length of its side

Let the length and the diagonal of the square be represented by L and D, respectively.

So that

D = 12.73

The relationship between the diagonal and the length of a square is given by the Pythagoras theorem as follows:

D^{2} = L^{2} + L^{2}

Solving further, we have

D^{2} = 2L^{2}

Divide both sides by 2

\frac{D^{2}}{2} = \frac{2L^{2}}{2}

\frac{D^{2}}{2} = L^2

Take Square root of both sides

\sqrt{\frac{D^{2}}{2}} = \sqrt{L^2}

\sqrt{\frac{D^{2}}{2}} = L

Reorder

L = \sqrt{\frac{D^{2}}{2}}

Now, the value of L can be calculated by substituting 12.73 for D

L = \sqrt{\frac{12.73^{2}}{2}}

L = \sqrt{\frac{162.0529}{2}}

L = \sqrt{{81.02645}

L = 9.001469325

L = 9.0015 (Approximated)

Hence, the length of the sides of the square is approximately 9.0015

7 0
3 years ago
McGill pick 9 apples Andy picks four <br> apples how many fewer apples did Andi pick Ben McGill
inysia [295]
McGill picked 9 and andi picked 4 so 9-4=5
andi picked 5 apples less than mcgill
3 0
3 years ago
Convert the following repeating decimal to a fraction in simplest form .53
galben [10]

9514 1404 393

Answer:

  53/99

Step-by-step explanation:

When an n-digit repeat begins at the decimal point, the repeating digits can be placed over an equal number of 9s to make a fraction. Sometimes, that fraction can be reduced to lower terms.

  0.\overline{53}=\boxed{\dfrac{53}{99}}

__

If the repeat does not start at the decimal point, the conversion can be done as follows.

For a number x with a decimal fraction that has n digits repeating, multiply by 10^n, subtract x and then divide by (10^n -1).

The fraction will be ...

  (x·10^n -x)/(10^n -1) . . . where x has n repeating digits in the decimal fraction

Here, that looks like ...

  x=0.\overline{53}\\100x=53.\overline{53}\\100x-x=53.\overline{53}-0.\overline{53}=53\\99x=53\\x=\dfrac{53}{99}

5 0
3 years ago
Multiply and simplify: x+4/x-5*x-1/x^2+2x-8
____ [38]
Hope it could help u

7 0
4 years ago
It's super easy!!<br><img src="https://tex.z-dn.net/?f=%20%5Ccos%20%5Ctheta%20%5C%3A%20%20%2B%20%20%5Ctan%20%5Ctheta%20%3D%20" i
valina [46]

Answer:

\frac{cos^{2} \theta + sin\theta}{cos\theta}

Step-by-step explanation:

Solving :

  • cos\theta + tan\theta
  • cos\theta + \frac{sin\theta}{cos\theta}
  • \frac{cos^{2} \theta + sin\theta}{cos\theta}
4 0
2 years ago
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