Question

A(n - 3) +8= bn for n please help me

Answer 1

Given equation: A(n - 3) +8= bn.

Solution: On the left side of the equation we have A(n-3).

We don't have any sign in between A and parenthesis (n-3).

So, we need to multiply A and (n-3).

We need to apply distributive property to multiply A and (n-3).

Distributing A over (n-3), we get

A(n-3) = A*n - 3*A = An -3A.

Substituting this value in original equation,

An -3A +8= bn.

We need to solve it for n, so we get n terms on a side.

We have An on left side, we need to get rid n from left side.

Subtracting An from both sides, we get

An -3A +8-An= bn-An.

-3A +8 = bn - An.

We can see n is a common factor on rigth side in bn-an.

Factoring out n on right side from bn-an.

-3A +8 = (b - A)n.

Dividing both sides by (b-A),

$\frac{(-3A+8)}{(b-A)} = \frac{(b-A)n}{(b-A)}$

On right (b-A) paranthiss cancelled and we get n on right side.

$\frac{(-3A+8)}{(b-A)} =n$   Final answer.

So, that would be our final answer

n = (-3A+8)/(b-A)