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patriot [66]
3 years ago
10

Find f(x) and g(x) such that h(x)=(f•g)(x) h(x)=4/x-8 Suppose that g(x)=x-8

Mathematics
1 answer:
solmaris [256]3 years ago
5 0

Answer:

i dont understand

Step-by-step explanation:

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768

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1x2x3=6

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2 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
ANTONII [103]
(x²+4x-12)/(x-2)=0
(x+6)(x-2)/(x-2)=0
x+6=0
x=-6
(-6,0)
8 0
3 years ago
Read 2 more answers
Use a system of linear equations with two variables and two equations to solve.
Pachacha [2.7K]

Answer:

passed: 164

failed: 41

Step-by-step explanation:

Let the failed students be x, then the passed students will be 4x.

x + 4x = 205

x = 205/5 = 41

4x = 4*41 = 164

7 0
2 years ago
4n² +7n=0 what do I do if there is no part c?
Gnoma [55]

Answer:

  • Find the coefficients using ax^2 + bx + c = 0

a = 4

b = 7

c = 0

  • Make the coefficient equal 1. But how do we do that? Division.

4n² + 7n = 0

4/4n² + 7n/4 = 0/4

  • Simplify

= n² + 7/4n = 0

a = 1

b = 7/4

c = 0

  • Complete the square using b/2².

b = 7/4

(b/2)² = (7/4 ÷ 2)²

Use fraction rule.

7/4 ÷ 2² = 7/4² / 2²

<em>square the numbers</em>

7/4² / 2² = 49/16 ÷ 4

49/16 ÷ 4 = 49/16 × 1/4

49/16 × 1/4 = 49/64

Add to both sides of the equation using 49/64

b = 7/4

b/2 = 7/4 ÷ 2

<em>simplify</em>

b/2 = 7 ÷ (4 × 2)

<em>simplify(arithmetic)</em>

b/2 = 7/8

n² + 7/4n + 49/64 = 49/64

(n + 7/8)² = 49/64

  • Solve for the unknown x

(n+\frac{7}{8})^2=\frac{49}{64}\\\sqrt{(n+\frac{7}{8})^2}=\sqrt{\frac{49}{64}}\\

Next, cancel out the square on the left side.

n+\frac{7}{8}=+/-\sqrt{\frac{49}{64}}

Subtract 7/8 from both of the sides.

n+\frac{7}{8}-\frac{7}{8}=-\frac{7}{8}+/-\sqrt{\frac{49}{64}}

Simplify the left side.

n=-\frac{7}{8}+/-\sqrt{\frac{49}{64}}\\n=-\frac{7}{8}+/-\frac{\sqrt{49}}{\sqrt{64}}\\n=-\frac{7}{8}+/-\frac{7}{8}\\n_1=0\\n_2=-\frac{7}{4}

<em>That wraps it up for this equation. Hope it helped!</em>

3 0
1 year ago
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