3 years ago

Write the equation of a line that is parallel to y= 3x-2 and that passes through (9,-5).

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

3 0

Answer:

y = -1/3x + 2

Step-by-step explanation:

The slopes of perpendicular lines are negative reciprocals.

The line y = 3x - 2 has slope 3.

The perpendicular line has slope -1/3.

Now we find the equation of the line that has slope -1/3 and passes through (-9, 5).

y = mx + b

y = -1/3x + b

5 = (-1/3)(-9) + b

5 = 3 + b

b = 2

The equation of the perpendicular is

y = -1/3x + 2

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