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Mandarinka [93]
3 years ago
7

The base of a triangle is 10 inches more than 3 times the height. If the area of the triangle is 16 square inches, find the base

and the height
Mathematics
1 answer:
USPshnik [31]3 years ago
8 0

Let h represent the height of the triangle.

... b = 10 + 3h . . . . . . the base is 10 inches more than 3 times the height

... A = (1/2)bh . . . . . . formula for the area of a triangle in terms of base and height

... 16 = (1/2)(10 +3h)h . . . . substitute the known values

... 3h² + 10h - 32 = 0 . . . . rearrange to standard form

... (h -2)(3h +16) = 0

... h = 2 or -16/3 . . . . . . . . the negative solution is extraneous

... b = 10 + 3·2 = 16 . . . . . use the relation between b and h

The base and height of the triangle are 2 inches and 16 inches, respectively.

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Solve the inequality 15 ≥ q + 3
oksano4ka [1.4K]

Answer:

q\le \:12

Step-by-step explanation:

<u>Solving</u>

\mathrm{Switch\:sides}  (Not a required step)

q+3\le \:15

\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}

q+3-3\le \:15-3\\=q\le \:12

\bold{q\le \:12}

<u>Graphing</u>

5 0
2 years ago
A conical perfume bottle has a radius of 3.4 centimeters and a height of 4.8 centimeters . Using 3.14 for pi, approximately how
Ghella [55]

Answer:

58.077 cubic cm

Step-by-step explanation:

Given that:

  • height : 4.8 cm
  • radius: 3.4 cm

As we know that, the volume of a conical perfume bottle is as following:

V = (1/3) * π * r² * h

So perfume can the bottle hold is:

V = (1/3) * 3.14 * 3.4² * 4.8 = 58.077 cubic cm

Hope it will find you well

5 0
4 years ago
Read 2 more answers
Plz answer. only if correct
earnstyle [38]

Answer:10001.5%+10303990=f(g+2)

Step-by-step explanation:

i dont remeber how to do this cap

5 0
3 years ago
Find the standard form polynomial that represents this product. (6 - y - 4y^2)(-5 + 7y^2)​
Tema [17]

Answer:

  • -28y^4 - 7y^3 + 62y^2 + 5y - 30

Step-by-step explanation:

<u>Opening the parenthesis and simplifying by combining like terms:</u>

  • (6 - y - 4y^2)(-5 + 7y^2)​  =
  • 6(-5) +6(7y^2) - y(-5) -y(7y^2) -4y^2(-5) -4y^2(7y^2) =
  • -30 + 42y^2  + 5y - 7y^3 +20y^2 -28y^4 =
  • -28y^4 - 7y^3 + 62y^2 + 5y - 30

5 0
4 years ago
On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/
den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

Speed=\dfrac{Distance}{Time}

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

2.5=\dfrac{d}{t}

2.5t=d      ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

4=\dfrac{d}{t-15}

4(t-15)=d      ...(2)

From (1) and (2), we get

4(t-15)=2.5t

4t-60-2.5t=0

1.5t=60

t=40

Put t=40 in (1).

d=2.5(40)=100

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}

\text{Average speed}=\dfrac{200}{65}

\text{Average speed}\approx 3.08

Therefore, the average speed is 3.08 km/h.

3 0
4 years ago
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