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sasho [114]
4 years ago
5

calculate the volume of the prism by first finding the total number of half unit cubes that will fill it. there are 8 half unit

cubes in every unit cubes.​
Mathematics
1 answer:
babunello [35]4 years ago
7 0

Answer:

8 half units

Step-by-step explanation:

if there is one cube in ever unit its 8 x 1

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True or false: 4 (2x + y + 6) is equivalent to 8x + 4y + 24.<br> A true<br> B false
kenny6666 [7]

Answer:

A) true

Step-by-step explanation:

when you use the distributive property with the equation 4(2x + y + 6) you get 8x + 4y + 24

3 0
4 years ago
Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me​
o-na [289]

Answer:

\frac{3}{2}

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

                   = - cos60cosx - sin60sinx

                   = - \frac{1}{2} cosx - \frac{\sqrt{3} }{2} sinx

squaring to obtain cos² (120 + x)

= \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - \frac{1}{2}cosx + \frac{\sqrt{3} }{2}sinx

squaring to obtain cos²(120 - x)

= \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x + \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

= cos²x + \frac{1}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}(cos²x + sin²x) = \frac{3}{2}

                 

5 0
3 years ago
What value of b will cause the system to have an infinite number of solutions? A system of equations. y equals 6 x plus b. negat
Natasha_Volkova [10]

The value of b is 6 for which the system of equation will have an infinite number of solutions option third is correct.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have two linear equations:

y = 6x - b ..(1)

\rm -3x + \dfrac{1}{2}y = -3 ..(2)

From the second equation:

\rm -3x + \dfrac{1}{2}y = -3

-6x + y = -6

After rearranging:

y = 6x - 6 ..(3)

On comparing equation (1) and (3)

b = 6

Thus, the value of b is 6 for which the system of equation will have an infinite number of solutions option third is correct.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

8 0
2 years ago
One bag of rice that weighs 4.5 pounds will have enough rice if a recipe calls for 60 ounces of rice. (1 pound = 16 ounces)
krek1111 [17]

the bag of rice weighs 4.5 pounds


Multiply 4.5 with 16 oz (as 1 lb = 16 oz)


4.5 x 16 = 72.


The bag of rice has 72 oz of rice inside.


The recipe only needs 60 oz of rice ∴ True, you will have enough, with 12 oz left over.



hope this helps

8 0
3 years ago
Iris weighed 5 large watermelons from her garden. Here are the weights in pounds. 17,11,21,24,22 what is the mean weight
Rufina [12.5K]

Answer:

Mean weight = 19 pounds

Step-by-step explanation:

From the question given above, the following data were obtained:

17, 11, 21, 24, 22

Number of data (n) = 5

Mean weight =?

The mean of a set of data is the value obtained by adding all the data together and dividing the result obtained by the total number of data. Thus, the mean can be obtained as follow:

Summation of data = 17+ 11 + 21 + 24 + 22

= 95

Number of data = 5

Mean = Summation of data / Number of data

Mean = 95 / 5

Mean weight = 19 pounds

Therefore, the mean weight of the data is 19 pounds

5 0
3 years ago
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