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alexdok [17]
2 years ago
15

Which expression can be used to find the value of X?

Mathematics
2 answers:
IRINA_888 [86]2 years ago
6 0
<span><span>Use the Law of Sines to find side b.</span><span> 
b / sin(B) = a / sin(A)</span><span> 
b / sin(32°) = 11 / sin(47°)</span><span> 
b = (sin(32°) x 11) / sin(47°)</span><span> <---- You would use this, so rewritten
11(sin(32))/sin(47) would be the expression, or answer B.)

BTW b = <span>7.970

Hope this helps!
</span></span></span>
liq [111]2 years ago
4 0

the correct answer is C) 11(sin32°) / sin47°

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a crew workers paved 2/15 mile in 20 minutes. if they work at the same rate what portion of a mile will they pave in one hour?
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Since 20 min is 1/3 of a mile 20 min*3=1 hour. then u multiply 2/5 by 3 to get 6/5.
6 0
3 years ago
Someone pls help asap this is due tmrw !!<br><br> x - 3y = -12<br> 2x + 3y = 3
hram777 [196]

Answer:

Step-by-step explanation:

to solve this system of equations we will add them

x-3y=-12

2x+3y=3 now +3y-3y=0

3x=-12+3

3x=-9

x=-3

plug in the first equation

-3-3y=-12

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4 0
2 years ago
A banks loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviati
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Answer:

2.87%

Step-by-step explanation:

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mean (m) = 200

standard deviation (sd) = 50

sample size = n = 40

the probability that their mean is above 21.5 is determined as follows:

P (x> 21.5) = P [(x - m) / (sd / n ^ (1/2))> (21.5 - 200) / (50/40 ^ (1/2))]

P (x> 21.5) = P (z> -22.57)

this value is very strange, therefore I suggest that it is not 21.5 but 215, therefore it would be:

P (x> 215) = P [(x - m) / (sd / n ^ (1/2))> (215 - 200) / (50/40 ^ (1/2))]

P (x> 215) = P (z> 1.897)

P (x> 215) = 1 - P (z <1.897)

We look for this value in the attached table of z and we have to:

P (x> 215) = 1 - 0.9713 (attached table)

P (x> 215) =.0287

Therefore the probability is approximately 2.87%

4 0
3 years ago
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3 years ago
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svp [43]

Answer:

The value of the car will be 6100 dollars in 8.8 years

Step-by-step explanation:

Present value of car = $23900

The value of the car depreciates at 14.25% per year

Let x be no. of years in which  the value of the car becomes 6100 dollars

Formula: N(t)=N_0(1-r)^t

Substitute the values :

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Hence the value of the car will be 6100 dollars in 8.8 years

7 0
3 years ago
Read 2 more answers
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