All categories

3 years ago

Write This number in expanded form 719,927

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

6 0

700,000 + 10,000 + 9,000 + 900 + 20 + 7

earnstyle [38]3 years ago

4 0

Seven hundred nine thousand and nine hundred twenty seven

You might be interested in

We call a number a descending number if each digit is strictly smaller than the digit that comes before it. For example, $863$ i

Mnenie [13.5K]

There are 120 of 3-digit descending numbers in total.

There is just one three-digit number that is a falling number if 2 is in the hundreds position, and that number is 210.

There are three such descending numbers if the number three is in the hundreds location.

310

320

321

Six descending numbers are available if 4 is in the hundreds place.

410

420

421

430

431

432

We have 10 descending numbers if the number five is in the hundreds location.

510

520

521

530

531

532

540

541

542

543

The current totals are: 1, 3, 6, and 10.

A +2 jump occurs from 1 to 3.

There is a +3 jump from 3 to 6.

From 6 to 10, there is a +4 jump.

Since there are 15 descending numbers and 6 is the hundreds digit, they are as follows: 610 620 621 630 631 632 640 641 642 643 650 651 652 653 654

Also included are the descending numbers 15+6 = 21 with the hundreds digit 7; 21+7 = 28 with the hundreds digit 8; and 28+8 = 36 with the hundreds digit 9.

They are 1,3,6,10,15,21,28, and 36.

1+3+6+10+15+21+28+36.

Equals 120 when added together.

Thus, there are 120 of 3-digit descending numbers in total.

Learn more about descending numbers at

brainly.com/question/13193576

#SPJ4

7 0

2 years ago

A circular region has a population of about 15,500 people and a population density of about 775 people per square kilometer. Fin

Reil [10]

Answer:

2.5 km

Step-by-step explanation:

First, find the area of the region:

A circular region has a population of about 15,500 people;
A population density of about 775 people per square kilometer.

So, there are $15,500 :775=20$ square kilometers.

Now, let x kilometers be the radius of the circular region, then

$A_{\text{circilar region}}=\pi r^2\\ \\20=\pi r^2\\ \\r^2=\dfrac{20}{\pi}\approx 6.366198\\ \\r=\sqrt{3.366198}\approx 2.523$

To the nearest tenth this is 2.5 km.

6 0

3 years ago

I need help with this problem 23 in to 61,982 not sure how to work the problem

Korolek [52]

What exactly is the problem? , there isn’t a photo or a description of what the problem is.

6 0

3 years ago

Solve for x THANK YOU

Anestetic [448]

Answer:

$x=\dfrac{-17+ \sqrt{451} }{18}, \quad x=\dfrac{-17- \sqrt{451} }{18}$

Step-by-step explanation:

$\textsf{Given equation}:$

$\dfrac{2}{3}x+\dfrac{3x}{x}=\dfrac{4x}{2}(3x+6)$

$\textsf{Cancel the common factor } x \textsf{ in }\dfrac{3x}{x}:$

$\implies \dfrac{2}{3}x+3=\dfrac{4x}{2}(3x+6)$

$\textsf{Simplify }\dfrac{4x}{2}\textsf{ by dividing the numbers}:$

$\implies \dfrac{2}{3}x+3=2x(3x+6)$

$\textsf{Apply the distributive law}\quad \:a\left(b+c\right)=ab+ac:$

$\implies \dfrac{2}{3}x+3=6x^2+12x$

$\textsf{Multiply both sides by 3 to cancel the denominator of }\dfrac{2}{3}:$

$\implies \dfrac{2}{3}x\cdot 3+3\cdot 3=6x^2\cdot 3+12x \cdot 3$

$\implies 2x+9=18x^2+36x$

$\textsf{Switch sides}:$

$\implies 18x^2+36x=2x+9$

$\textsf{Subtract }2x \textsf{ from both sides}:$

$\implies 18x^2+36x-2x=2x+9-2x$

$\implies 18x^2+34x=9$

$\textsf{Subtract 9 from both sides}:$

$\implies 18x^2+34x-9=9-9$

$\implies 18x^2+34x-9=0$

Solve using the Quadratic Formula:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Define the variables:

$\implies a=18, \quad b=34, \quad c=-9$

Substitute the defined variables into the quadratic formula and solve for x:

$\implies x=\dfrac{-34 \pm \sqrt{34^2-4(18)(-9)} }{2(18)}$

$\implies x=\dfrac{-34 \pm \sqrt{1156+648} }{36}$

$\implies x=\dfrac{-34 \pm \sqrt{1804} }{36}$

$\implies x=\dfrac{-34 \pm \sqrt{4 \cdot 451} }{36}$

$\implies x=\dfrac{-34 \pm \sqrt{4}\sqrt{451} }{36}$

$\implies x=\dfrac{-34 \pm 2\sqrt{451} }{36}$

$\implies x=\dfrac{-17 \pm \sqrt{451} }{18}$

Therefore, the solutions to the given equation are:

$x=\dfrac{-17+ \sqrt{451} }{18}, \quad x=\dfrac{-17- \sqrt{451} }{18}$

Learn more about the Quadratic Formula here:

brainly.com/question/28105589

brainly.com/question/23700639

3 0

2 years ago

Read 2 more answers

Please help! Double points!

S_A_V [24]

Answer:

$\frac{13}{18}$ (72.22%)

Step-by-step explanation:

For this question, you must get at least one blue block. However, you can also think of it this way: pretend the other seven blocks are red (it does not matter since the colors other than blue do not matter) what is the probability that you do not only get red blocks?

You can calculate the probability that you only get red blocks simply with multiplication rule:

$\frac{7}{9} *\frac{6}{8} *\frac{5}{7} *\frac{4}{6}$ $=\frac{5}{18}$

(not the numbers increment down because they are not replaced)

Then, you use the fact that having red blocks and not having red blocks as a complement to calculate the probability

$1-\frac{5}{18}$ $=\frac{13}{18}$

This is your final answer: 72.22%

7 0

2 years ago