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3 years ago

What algebraic expressionis an polynomail with a degree of 4

Mathematics

1 answer:

MAXImum [283]3 years ago

8 0

Answer:

The algebraic expression with a degree of 4 is 9x^4 – x^3.

Step-by-step explanation:

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PLEASE HELP EMERGENCY!! IF YOU ARE NOT 100% SURE ABOUT YOUR ANSWER DO NOT ANSWER THEN!! PLEASE!!

Black_prince [1.1K]

Answer:

A -$66.65

Step-by-step explanation:

4.50x 14 = 63.00 in penalties

-63.00 + - 3.65 = -66.65

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3 years ago

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you shopping cart has a mass of 65 kilograms in order to accelerate the shopping cart down an aisle at 0.3m/s2 what force would

sergeinik [125]

Did the team's value increase from 2015 to 2016?

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3 years ago

The height of a football during a punt is modeled by h=-16t^2+60t+3. If the football hits the ground, how long did it stay in th

weqwewe [10]

"how long..." is asking for time (t). "The amount of time spent in the air" is the time from when the ball was kicked (0 seconds) to the time it landed on the ground. Need to find the x-intercepts (one will be negative which will be invalid). You can do this by factoring ... <em>or by using the quadratic formula.</em> With the equation you provided, it is not factorable, so you must use the quadratic formula.

h = -16t² + 60t + 3

a=-16 b=60 c=3

$t = \frac{-b +/- \sqrt{b^{2}-4ac } }{2a}$

$t = \frac{-60 +/- \sqrt{60^{2}-4(-16)(3) } }{2(-16)}$

$t = \frac{-60 +/- \sqrt{3600 + 192} }{-32}$

$t = \frac{-60 +/- \sqrt{3792} }{-32}$

$t = \frac{-60 +/- 61.6}{-32}$

$t = \frac{-60 + 61.6}{-32}$ or $t = \frac{-60 - 61.6}{-32}$

$t = \frac{1.6}{-32}$ or $t = \frac{-121.6}{-32}$

t = -0.05 or t = 3.8 <em>disregard the negative</em>

Answer: 3.8 seconds

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3 years ago

In a 4x4x4 cube, the face is painted red, then divided into 64 1x1x1 cubes. How many of the 1x1x1 cubes are painted 1 or 2 faces

WITCHER [35]

Is 28 I think I am not sure

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3 years ago

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We did not find results for: A measure of malnutrition, called the pelidisi, varies directly as the cube root of a person's w

asambeis [7]

$\bf \qquad \qquad \textit{double proportional variation}\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\$

$\bf \begin{cases}
p=pedalisi\\
w=weight\\
s=\textit{sitting height}
\end{cases}\quad 
\begin{array}{llll}
%pelidisi, varies directly as the cube root of a person's weight in grams and inversely as the person's sitting height in centimeters.
\textit{pelidisi varies directly}\\
\textit{as cube root of weight}\\
\textit{and inversely to }\\
\textit{sitting height}
\end{array}\implies p=\cfrac{k\sqrt[3]{w}}{s}\\\\
-------------------------------$

$\bf \textit{we know that }
\begin{cases}
w=48,820\\
s=78.7\\
p=100
\end{cases}\implies 100=\cfrac{k\sqrt[3]{48820}}{78.7}
\\\\\\
100\cdot 78.7=k\sqrt[3]{48820}\implies \cfrac{7870}{\sqrt[3]{48820}}=k
\\\\\\
thus\qquad \boxed{p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{w}}{s}}
\\\\\\
\textit{now, what is \underline{p} when }
\begin{cases}
w=54,688\\
s=72.6
\end{cases}?\implies p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{54688}}{72.6}$

now, if that value is less than 100, then the fellow is "undernourished", otherwise, is overfed.

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3 years ago