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2 years ago

Which equation represents a line which is parallel to the line 7x - y = 4?

Mathematics

1 answer:

koban [17]2 years ago

6 0

Answer:

Step-by-step explanation: step : Place the given line’s equation in slope- intercept form y = mx + b. A line parallel to this line will have the same slope.

7x - y = 4. Yields y = 7 x - 4. Therefore y = 7x - 5 is the correct answer.

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The first three steps in writing f(x) = 40x + 5x2 in vertex form are shown. What is the function written in vertex form?

pychu [463]

F(x) = 5(x + 4) – 80
f(x) = 5(x + 8) – 80
f(x) = 5(x + 4)2 – 80
f(x) = 5(x + 8)2 – 80

4 0

3 years ago

I need help, an answer or how to- will be fine, thank you. (i’ll mark brainliest if i can)

siniylev [52]

by solving the first equation you'll get x= -24/13

if you solve the second option (B) then you'll the same result i.e x=-24/13

so option C is correct

7 0

3 years ago

Is the given value a solution to the equation? 4(n) - 3 = -2(n) + 9 n=2

nlexa [21]

Answer:

Yes!

The solution to the equation is n = 2

Step-by-step explanation:

Given the equation

$4\left(n\right)-3=-2\left(n\right)+9$

remove the parentheses

$4n-3=-2n+9$

Add 3 to both sides

$4n-3+3=-2n+9+3$

Simplify

$4n=-2n+12$

Add 2n to both sides

$4n+2n=-2n+12+2n$

Simplify

$6n=12$

Divide both sides by 6

$\frac{6n}{6}=\frac{12}{6}$

Simplify

$n=2$

Therefore, the value of n = 2.

Hence,

Yes!

The solution to the equation is n = 2

5 0

3 years ago

Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2

LUCKY_DIMON [66]

Make a change of coordinates:

$u(x,y)=xy$
$v(x,y)=\dfrac xy$

The Jacobian for this transformation is

$\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}$

and has a determinant of

$\det\mathbf J=-\dfrac{2x}y$

Note that we need to use the Jacobian in the other direction; that is, we've computed

$\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}$

but we need the Jacobian determinant for the reverse transformation (from $(x,y)$ to $(u,v)$ . To do this, notice that

$\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}$

we need to take the reciprocal of the Jacobian above.

The integral then changes to

$\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv$
$=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2$

8 0

3 years ago

the distance from the origin to point p is 5 units. give the coordinates of four possible locations for point p

yan [13]

All I can think of is (5,0) (0,5)
Hopefully it helps.

4 0

3 years ago