3 years ago

Find X in both problems using the pythagorean theorem

Mathematics

1 answer:

malfutka [58]3 years ago

5 0

Answer:

first X=8.94

second X=34

Step-by-step explanation:

5) x^2=4^2+8^2

x^2=16+64=80

x=8.94

6)x^2= 31^2+14^2

x^2=961+196

x^2=1157

x=34

You might be interested in

Simplify each ratio. <br><br> 1) 40:15

Vilka [71]

Answer:

8:3

Step-by-step explanation:

,,,,lol hope it helps i don't know how to explain,,, I guess its just dividing you know like 15÷5= 3 so on

3 0

3 years ago

Need that help.......plz

Anika [276]

For Question Number one
(2+10)²+4=148

Question Number two:
(6+5)×(8-6)=22

5 0

3 years ago

In the equation (m^5/6) (m^1/6)^7 = m^x , what is the value of x that makes the equation true?

vlabodo [156]

${m}^{ \frac{5}{6} } \times (m {}^{ \frac{1}{6} } ) {}^{7 } = m {}^{x}$

$m {}^{ \frac{5}{6} } \times m {}^{ \frac{7}{6} } = m {}^{x}$

${m}^{ \frac{5 \times 7}{6 \times 6} } = {m}^{x}$

$\frac{35}{36} = x$

6 0

2 years ago

Anyone know this if so please help

Likurg_2 [28]

24. 9×4=36 4×-3=12 so 36+(-12)=24

7 0

3 years ago

Read 2 more answers

Write a number that has a zero in the tens place draw a quick picture of your numbers

tatuchka [14]

Answer:

Literally any number will do.

Step-by-step explanation:

26,201

There

4 0

3 years ago