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svetoff [14.1K]
2 years ago
5

Which adjustment would turn the equation y = -3x^2+4 into a linear function?

Mathematics
2 answers:
monitta2 years ago
7 0

Answer:

A.

Step-by-step explanation:

Sveta_85 [38]2 years ago
3 0
A is the answer. Take 4 out of the equation
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She serves the drinks at the interval. She serves 40 drinks in 20 minutes. What is the mean time she takes to serve 1 drink?
Alex Ar [27]
It takes her 2 minutes to serve 1 drink.
5 0
3 years ago
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Please help me find the value of X
Ymorist [56]

Answer:

Is this

Step-by-step explanation:

3 0
3 years ago
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Explain your answer, please
Molodets [167]

.1.Scale Factor of Triangle STU to Triangle PQR= 1.5

2.Scale Factor of Trapezoid EFGH to Trapezoid JKLM =2

3. about 90 armadillo

1.Side ST: 15 ÷ Side PQ: 10 = 1.5

2.Side JM: 14 ÷Side EH: 7 = 2

3.843/7=120.428571429

843/4=210.75

210.75-120.428571429=90.321428571

This rounds to 90 armadillo

Hope this helps :3 ❤

8 0
3 years ago
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Determine the astm grain size number if 33 grains per square inch are measured at a magnification of 270×
strojnjashka [21]
8.9

The equation for the grain size is expressed as the equality:
Nm(M/100)^2 = 2^(n-1)
where
Nm = number of grains per square inch at magnification M.
M = Magnification
n = ASTM grain size number

Let's solve for n, then substitute the known values and calculate.
Nm(M/100)^2 = 2^(n-1)

log(Nm(M/100)^2) = log(2^(n-1))
log(Nm) + 2*log(M/100) = (n-1) * log(2)
(log(Nm) + 2*log(M/100))/log(2) = n-1
(log(Nm) + 2*log(M/100))/log(2) + 1 = n

(log(33) + 2*log(270/100))/log(2) + 1 = n
(1.51851394 + 2*0.431363764)/0.301029996 + 1 = n
(1.51851394 + 0.862727528)/0.301029996 + 1 = n
2.381241468/0.301029996 + 1 = n
7.910312934 + 1 = n
8.910312934 = n

So the ASTM grain size number is 8.9

If you want to calculate the number of grains per square inch, you'd use the
same formula with M equal to 1. So:
Nm(M/100)^2 = 2^(n-1)
Nm(1/100)^2 = 2^(8.9-1)
Nm(1/10000) = 2^7.9
Nm(1/10000) = 238.8564458
Nm = 2388564.458

Or about 2,400,000 grains per square inch.
7 0
3 years ago
Carlos has 2,175 marbles in his collection . Emily has 1833 marbles in her collection . Carlos says that he has about 1,000 more
kenny6666 [7]
Carlos is wrong since when subtracted 2175 from 1833 you get 342 so that's about one third of what he said.
5 0
3 years ago
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