All categories

2 years ago

Find a solution to the following system of equations. –2x + 5y = 8 2x + 2y = 6

2 answers:

4 0

-2x + 5y = 8
2x + 2y = 6
----------------add
7y = 14
y = 14/7
y = 2

2x + 2y = 6
2x + 2(2) = 6
2x + 4 = 6
2x = 6 - 4
2x = 2
x = 2/2
x = 1

solution is (1,2)

enot [183]2 years ago

4 0

Add the two equations to eliminate x:
-2x + 5y = 8
+
2x + 2y = 6
=
7y = 14 so y = 2.
Sub y into an equation as 2, so if you take the 2nd equation you get:
2x + (2*2) = 6, so 2x = 2, x=1.

You might be interested in

Please help... I have no clue

muminat

Answer:

OPTION C: Sin C - Cos C = s - r

Step-by-step explanation:

ABC is a right angled triangle. ∠A = 90°, from the figure.

Therefore, BC = hypotenuse, say h

Now, we find the length of AB and AC.

We know that: $\textbf{Sin A} = \frac{\textbf{opp}}{\textbf{hyp}}$

and $\textbf{Cos A} = \frac{\textbf{adj}}{\textbf{hyp}}$

Given, Sin B = r and Cos B = s

⇒ $Sin B = r = \frac{opp}{hyp} = \frac{AC}{BC} = \frac{AC}{h}$

⇒ $\textbf{AC} = \textbf{rh}$

Hence, the length of the side AC = rh

Now, to compute the length of AB, we use Cos B.

$Cos B = s = \frac{adj}{hyp} = \frac{AB}{BC} = \frac{AB}{h}$

⇒ $\textbf{AB} = \textbf{sh}$

Hence, the length of the side AB = sh

Now, we are asked to compute Sin C - Cos C.

$Sin C = \frac{opp}{hyp}$

⇒ $Sin C = \frac{AB}{BC}$

$= \frac{sh}{h}$

= s

Sin C = s

$Cos C = \frac{adj}{hyp}$

$\implies Cos C = \frac{AC}{BC}$

⇒ Cos C = $\frac{rh}{h}$

Therefore, Cos C = r

So, Sin C - Cos C = s - r, which is OPTION C and is the right answer.

5 0

3 years ago

Hannah uses a store gift card to pay for 3 pair of pants priced at $27 each. What is the change in

kicyunya [14]

Answer:

If the gift card is $30 the remaining change is 3 dollars

5 0

3 years ago

Answer to this quest

Drupady [299]

Answer:

Point A to point F and point I to point H would have the ratio of 2:1.

3 0

2 years ago

Suppose that in an alternate universe, the gambler's fallacy is true: the more a gambler loses, the more likely she is to win th

stepladder [879]

Answer and explanation:

The gambler's fallacy is the fallacy of belief that if an event such as a loss occurs more frequently in the past, it is less likely to happen in the future. We assume here that this belief is true, therefore

If she loses, her probability of winning increases =3/4

If she wins, her probability to win is normal =1/2

Given that probability of winning is 1/2

Probability of losing is 1-1/2=1/2

Probability that she wins the tournament is probability that she wins the first two games and loses the last or wins the first game, loses the second and wins the last or loses the first game and wins the last two games or probability that she wins all three games

=1/2*1/2*1/2+1/2*1/2*3/4+1/2*3/4*1/2+1/2*1/2*1/2

=25/48

Probability of winning the tournament if she loses the first game

=1/2*3/4*1/2= 3/16

Note: whenever there is "or" in probability, you add

4 0

3 years ago

The distance from the center of a carousel to the

anzhelika [568]

Answer:

$\fbox{\begin{minipage}{3.5em}338 (ft)\end{minipage}}$

Step-by-step explanation:

The problem could be simplified as following:

Given:

The radius of a circle O is 26 feet.

Solve for:

The length of arc on circle O that measures 13 radians

Solution:

Step 1: Let's find out the correct formula to apply:

The formula to calculate the length of an arc measuring x radians on a circle with radius r feet is:

L = r*x

Step 2: Let's put the data into formula to work out the length L of arc:

L = 26*13 = 338 (ft)

=> The distance that a horse does on the outer edge travel when the carousel rotates through 13 radians: L = 338 (ft)

Hope this helps!

7 0

3 years ago